我正在開發一個 Symfony 項目，其中有兩種類型的 User Client 和 EmployeSpie，兩者都有自己的實體。當您創建/編輯用戶時，您可以將 EmployeSpie 鏈接到客戶端。這就是我的問題所在，當我編輯或創建用戶時，我可以創建一個用戶，但我的表中沒有存儲任何內容來建立我的表 Client 和 EmployeSpie 之間的鏈接。這是我所做的：我的實體客戶有這樣的：class Client extends User{    /**     * @ORM\ManyToMany(targetEntity=EmployeSpie::class, mappedBy="clients", cascade={"persist"})     */    private $employeSpies;     /**     * @return Collection|EmployeSpie[]     */    public function getEmployeSpies(): Collection    {        return $this->employeSpies;    }    public function addEmployeSpy(EmployeSpie $employeSpy): self    {        if (!$this->employeSpies->contains($employeSpy)) {            $this->employeSpies[] = $employeSpy;            $employeSpy->addClientEmploye($this);        }        return $this;    }    public function removeEmployeSpy(EmployeSpie $employeSpy): self    {        if ($this->employeSpies->contains($employeSpy)) {            $this->employeSpies->removeElement($employeSpy);            $employeSpy->removeClientEmploye($this);        }        return $this;    }}和我的表 EmployeSpie：class EmployeSpie extends User{    /**     * @ORM\ManyToMany(targetEntity=Client::class, inversedBy="employeSpies")     */    private $clients;    /**     * @return Collection|Client[]     */    public function getClients(): Collection    {        return $this->clients;    }    public function addClient(Client $client): self    {        if (!$this->clients->contains($client)) {            $this->clients[] = $client;        }        return $this;    }    public function removeClient(Client $client): self    {        if ($this->clients->contains($client)) {            $this->clients->removeElement($client);        }        return $this;    }    public function __toString()    {        return $this->getPrenom()." ".$this->getNom();    }