如何創建一個函數來查找對象數組的數據，而不給出與對象值匹配的精確搜索值。例如我的數組是：const array = [{    "name": "Max Messi",    "age": 21,    "gender": "male"},{    "name": "tina baidya",    "age": 10,    "gender": "female"},{    "name": "tina shrestha",    "age": 100,    "gender": "female"}]現在我想要一個函數來返回所有包含“tina”的數據name。我嘗試使用array.filter()方法，但它需要精確的搜索名稱。就像我需要打字tina shrestha而不是僅僅tina這是我嘗試過的：const array = [{    "name": "Max Messi",    "age": 21,    "gender": "male"},{    "name": "Lina baidya",    "age": 10,    "gender": "female"},{    "name": "tina shrestha",    "age": 100,    "gender": "female"}]function findData(data, id){    const found = data.filter(element => element.name === id)    return found}console.log(findData(array, "tina"))//logs empty array as i need to type full search value那么我怎樣才能創建搜索 json 數據的函數而不輸入確切的值。