我有一系列權限const permissions = ['search', 'reports', 'whitelist'];我有一個菜單const menus = [  {    text: 'Navigation',    link: 'navigation',    topic: 'all',  },  {    text: 'Dictionary',    link: 'dict',    topic: 'src',  },  {    text: 'Services',    link: '/services',    submenu: [      {        text: 'Check company',        link: '/services/search',        topic: 'search',      },      {        text: 'Report statistic',        link: '/services/reportstatistic',        topic: 'another-topic',      },      {        text: 'Report request',        link: '/services/getrequestreport',        topic: 'another-topic-2',      },      {        text: 'Get whitelist',        link: '/services/getresponsereport',        topic: 'whitelist',      },      {        text: 'Get data',        link: '/services/requestdata',        topic: 'reports',      },    ],  },];我需要過濾menus以檢查數組的每一項是否topic等于數組中的一項權限permissions，如果它具有submenu，則檢查每個項目表單子菜單是否相同或是否topic ==='all'并將其添加到新菜單中。過濾后的預期結果是const newArrr = [  {    text: 'Navigation',    link: 'navigation',    topic: 'all',  },  {    text: 'Services',    link: '/services',    submenu: [      {        text: 'Check company',        link: '/services/search',        topic: 'search',      },      {        text: 'Get whitelist',        link: '/services/getresponsereport',        topic: 'whitelist',      },      {        text: 'Get data',        link: '/services/requestdata',        topic: 'reports',      },    ],  },];我試圖制作自己的循環，但它不正確for (let menu of menus) {  for (let permission of filteredPermissions) {    if (menu.topic && (menu.topic == permission || menu.topic === 'all')) {      newArr.push(menu);    }    if (menu.submenu) {      for (let submenu of menu.submenu) {        for (let permissionSecond of filteredPermissions) {          if (!(submenu.topic == permissionSecond) || !(submenu == 'all')) {            menu.submenu.splice(menu.submenu[submenu], 1);          }        }      }    }  }}