我創建了一個具有多個用戶的網站，使用圖像發布帖子并能夠添加/刪除朋友。因此，很容易為帖子列表創建兩個不同的頁面并創建一個新頁面。但當然，當你可以在同一個地方閱讀帖子并發布新帖子時，它看起來會更好。據我了解（學習 django 不到一個月），我無法將 2 個視圖連接到同一個 url，所以我看到的最合乎邏輯的方法是將 2 個視圖連接到一個視圖中，我還嘗試使用模板繼承來渲染通過包含模板發布表單，但實際上它不起作用。下面你可以看到我的觀點、帖子模型和模板。感謝您的關注。views.py:from braces.views import SelectRelatedMixinfrom . import modelsfrom django.views import genericfrom django.contrib.auth.mixins import LoginRequiredMixinclass PostList(SelectRelatedMixin, generic.ListView): model = models.Post select_related = ('user',)class CreatePost(LoginRequiredMixin, SelectRelatedMixin, generic.CreateView): fields = ('post_message', 'post_image') model = models.Post select_related = ('user',) def form_valid(self, form): self.object = form.save(commit = False) self.object.user = self.request.user self.object.save() return super().form_valid(form)models.py:import misakaclass Post(models.Model): user = models.ForeignKey(User, on_delete = models.CASCADE, related_name = 'posts') posted_at = models.DateTimeField(auto_now = True) post_message = models.TextField() message_html = models.TextField(editable = False) post_image = models.ImageField(upload_to = 'postpics', blank = True) def __str__(self): return self.post_message def save(self, *args, **kwargs): self.message_html = misaka.html(self.post_message) super().save(*args, **kwargs) def get_absolute_url(self): return reverse('posts:all') class Meta: ordering = ['-posted_at'] unique_together = ['user', 'post_message']urls.py:app_name = 'posts'urlpatterns = [ path('', views.PostList.as_view(), name = 'all'), path('new/', views.CreatePost.as_view(), name = 'create'),]post_form.html（模板，允許創建新帖子，將在 post_list.html 中看到）：
3 回答
炎炎設計
TA貢獻1808條經驗 獲得超4個贊
您可以將 post_create_form 與 post_list_view 放在同一頁面上，無需為帖子創建創建單獨的視圖，但您需要創建用于編輯和刪除的視圖。您可以為所有這些視圖提供具有不同 URL 的相同 HTML 頁面。在 Class_Based_Views 中使用template_name = 'example/example.html',。我希望我能理解您的問題，如果不能進一步澄清為什么您不能將兩個視圖合并為一個。
千萬里不及你
TA貢獻1784條經驗 獲得超9個贊
def posts(request):
posts = Post.objects.all()
form = PostForm(request.POST or None, request.FILES or None)
if request.method == "POST":
if form.is_valid():
...
context={
'posts' : page_obj,
'create_or_update_post_form' : form,
}
return render(request, 'post/posts.html',context)
您是否在基于類的視圖中很難做到這一點？
慕容3067478
TA貢獻1773條經驗 獲得超3個贊
您可以使用基于 django 類的視圖輕松完成。
創建視圖為
from django.views.generic import ListView
from django.views.generic.edit import CreateView
class ModelCreate(CreateView):
model = ModelName
fields = ['field1', 'field2']
template_name = 'same_page.html'
success_url = reverse_lazy('list_view')
class ModelList(CreateView, ListView):
model = ModelName
fields = ['field1', 'field2']
paginate_by = 5
template_name = 'same_page.html'
def get_context_data(self, *args, **kwargs):
context = super().get_context_data(*args, **kwargs)
context['form'] = self.get_form()
return context
# If form post redirect to ModelCreate View
def post(self, request, *args, **kwargs):
return ModelCreate.as_view()(request)
應用程序/urls.py
from django.urls import path
from app import views
path('list', views.ModelList.as_view(), name='list_view'),
path('add', views.ModelCreate.as_view(), name='add_view'),
最后在 templates/same_page.html 中
<div class="row">
<div class="col-sm-5">
<form method="post" enctype="multipart/form-data">
{% csrf_token %}
{{form.as_p}}
<button type="submit" value="submit" class="btn btn-primary btn-sm float-right">Submit</button>
</form>
</div>
<div class="col-sm-5">
{% if object_list %}
{% for object in object_list %}
<p>{{object.field1}}</p>
<p>{{object.field2}}</p>
{% endfor %}
{% endif %}
</div>
</div>
希望這可以幫助。
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