當我運行以下命令時import pandas as pddef my_func(E, I): return E * Id = {'E': [1, 1], 'I': [2, 2]}df = pd.DataFrame(data=d)df['S'] = df.apply(lambda x: my_func(x['E'], x['I']),axis=1).map(lambda x: x[0]) 我收到以下錯誤Traceback (most recent call last): File "U:\GSY\scipt.py", line 14, in <module> df['S'] = df.apply(lambda x: my_func(x['E'], x['I']),axis=1).map(lambda x: x[0]) File "C:\Users\gsy.LSH\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.8_qbz5n2kfra8p0\LocalCache\local-packages\Python38\site-packages\pandas\core\series.py", line 3630, in map new_values = super()._map_values(arg, na_action=na_action) File "C:\Users\gsy.LSH\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.8_qbz5n2kfra8p0\LocalCache\local-packages\Python38\site-packages\pandas\core\base.py", line 1145, in _map_values new_values = map_f(values, mapper) File "pandas\_libs\lib.pyx", line 2329, in pandas._libs.lib.map_infer File "U:\GSY\script.py", line 14, in <lambda> df['S'] = df.apply(lambda x: my_func(x['E'], x['I']),axis=1).map(lambda x: x[0])TypeError: 'int' object is not subscriptable我 100% 確信這在過去是有效的，因為我已經廣泛使用了它。有誰知道為什么會發生這種情況？
1 回答
慕虎7371278
TA貢獻1802條經驗 獲得超4個贊
最后把最后一張地圖扔掉就可以了。該函數正在返回一個列表，而您的最后一個映射函數正在嘗試獲取列表的第一個元素。
import pandas as pd
def my_func(E, I):
return E * I
d = {'E': [1, 1], 'I': [2, 2]}
df = pd.DataFrame(data=d)
df['S'] = df.apply(lambda x: my_func(x['E'], x['I']),axis=1)
或者，但根據此處的注釋，您可以將 my_func 的值作為列表返回：
import pandas as pd
def my_func(E, I):
return [E * I]
d = {'E': [1, 1], 'I': [2, 2]}
df = pd.DataFrame(data=d)
df['S'] = df.apply(lambda x: my_func(x['E'], x['I']),axis=1).map(lambda x: x[0])
添加回答
舉報
0/150
提交
取消