我有一本看起來像這樣的字典..results = {'agunii2035': ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000'], 'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'], 'agunii2006': ['agunii2035', 'agunii3007', 'agunii2003', 'agunii3000'], 'agunii2003': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii3000'], 'agunii3000': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii2003']}我還有另一本字典，有這樣的分數。score ={'agunii2035': [4, 4, 1, 3], 'agunii3007': [4, 3, 3, 1], 'agunii2006': [4, 3, 2, 2], 'agunii2003': [1, 3, 2, 1], 'agunii3000': [3, 1, 2, 1]}我想根據“分數”字典的值對“結果”字典的值進行排序。例如，對于鍵“agunii2035”，分數字典具有值 [ 4,4,1,3]。因此，我想對“結果”字典的值進行排序，以使用相同的鍵而['agunii3007', 'agunii2006', 'agunii3000','agunii2003']不是 ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000']。
2 回答
慕的地10843
TA貢獻1785條經驗 獲得超8個贊
results = {'agunii2035': ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000'],
'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'],
'agunii2006': ['agunii2035', 'agunii3007', 'agunii2003', 'agunii3000'],
'agunii2003': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii3000'],
'agunii3000': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii2003']}
score = {'agunii2035': [4, 4, 1, 3],
'agunii3007': [4, 3, 3, 1],
'agunii2006': [4, 3, 2, 2],
'agunii2003': [1, 3, 2, 1],
'agunii3000': [3, 1, 2, 1]}
ordered_results = {key:[item for _, item in
sorted(zip(score.get(key), value), reverse=True)]
for key, value in results.items()}
print(ordered_results)
輸出
{'agunii2035': ['agunii3007', 'agunii2006', 'agunii3000', 'agunii2003'],
'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'],
'agunii2006': ['agunii2035', 'agunii3007', 'agunii3000', 'agunii2003'],
'agunii2003': ['agunii3007', 'agunii2006', 'agunii3000', 'agunii2035'],
'agunii3000': ['agunii2035', 'agunii2006', 'agunii3007', 'agunii2003']}
寶慕林4294392
TA貢獻2021條經驗 獲得超8個贊
您需要做的就是使用從分數中查找字典的值作為對這樣的結果進行排序的鍵。這是可行的，因為默認排序算法可以使用列表作為排序依據。key: values然后，它使用字典理解從排序列表中構建一個新字典。
results = {
'agunii2035': ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000'],
'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'],
'agunii2006': ['agunii2035', 'agunii3007', 'agunii2003', 'agunii3000'],
'agunii2003': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii3000'],
'agunii3000': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii2003']
}
score = {
'agunii2035': [4, 4, 1, 3],
'agunii3007': [4, 3, 3, 1],
'agunii2006': [4, 3, 2, 2],
'agunii2003': [1, 3, 2, 1],
'agunii3000': [3, 1, 2, 1]
}
sorted_results = {
k: v
for k, v
in sorted(results.items(), key=lambda item: score[item[0]])
}
print(sorted_results)
# {'agunii2003': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii3000'], 'agunii3000': ['agunii2035', 'agunii3007', 'agunii2006', 'agunii2003'], 'agunii2006': ['agunii2035', 'agunii3007', 'agunii2003', 'agunii3000'], 'agunii3007': ['agunii2035', 'agunii2006', 'agunii2003', 'agunii3000'], 'agunii2035': ['agunii3007', 'agunii2006', 'agunii2003', 'agunii3000']}
添加回答
舉報
0/150
提交
取消