我正在嘗試學習 asyncio 和 aiohttp。我有以下代碼來使用 asyncio 查詢一堆 URL。import aiohttpimport asynciosync def fetch(session, url): async with session.get(url) as response: return await response.text()async def main(): urls = [ 'http://yahoo.com', 'https://google.com', 'http://bing.com' ] tasks = [] async with aiohttp.ClientSession() as session: for url in urls: tasks.append(fetch(session, url)) htmls = await asyncio.gather(*tasks) for html in htmls: print(html[:100] + "\n") if __name__ == '__main__': loop = asyncio.get_event_loop() loop.run_until_complete(main())如何獲取每個異步查詢的響應時間？我的第一個想法是只使用計時器，但我不知道在這種情況下如何使用它。我嘗試搜索是否有人做過類似的事情，但找不到任何東西。
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POPMUISE
TA貢獻1765條經驗 獲得超5個贊
async def fetch(session, url):
"""[Coroutine to send HTTP request to URLs provided]
Args:
session ([aiohttp Client Session object]): [session object]
url ([string]): [URL to query]
Returns:
[list]: [response url, status and time taken]
"""
tic = time.perf_counter() # Start timer
try:
response = await session.request(method='GET', url=url, timeout=10)
toc = time.perf_counter() # Stop timer
time_taken = toc - tic # Calculate time taken to get response
response.raise_for_status()
print("URL : ", url)
print("HTTP Status : ", response.status)
print(f"Time taken : {time_taken:4f} seconds")
print()
return str(response.url), response.status, time_taken
except HTTPError as http_err:
logging.error(http_err)
except Exception as err:
logging.error(err)
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