道路規則應用程序我有一個活動，其中將根據票號顯示問題和答案（20 個問題和 5x20 個答案）。字符串中包含的問題和答案重新排序并排序。我的代碼非常糟糕，我想通過循環來簡化，就像有問題 [q] 但有 2 個變量的情況一樣。請幫幫我。https://play.google.com/store/apps/details?id=ua.in.sil.cryzalit.mybiletsnumber = intent.getStringExtra("number");  for( int i = 1; i < 21; i++)    {        q[i]= this.getResources().getIdentifier("q"+i+"_" + number, "string", this.getPackageName());    }    int a1_1 = this.getResources().getIdentifier("a1_1_" + number, "string", this.getPackageName());    int a2_1 = this.getResources().getIdentifier("a2_1_" + number, "string", this.getPackageName());    int a3_1 = this.getResources().getIdentifier("a3_1_" + number, "string", this.getPackageName());    int a4_1 = this.getResources().getIdentifier("a4_1_" + number, "string", this.getPackageName());    int a5_1 = this.getResources().getIdentifier("a5_1_" + number, "string", this.getPackageName());\\\\    int a1_20 = this.getResources().getIdentifier("a1_20_" + number, "string", this.getPackageName());    int a2_20 = this.getResources().getIdentifier("a2_20_" + number, "string", this.getPackageName());    int a3_20 = this.getResources().getIdentifier("a3_20_" + number, "string", this.getPackageName());    int a4_20 = this.getResources().getIdentifier("a4_20_" + number, "string", this.getPackageName());    int a5_20 = this.getResources().getIdentifier("a5_20_" + number, "string", this.getPackageName());