我正在嘗試從用戶那里獲取 2 個點的輸入并輸出距離。我陷入了將輸入轉換為輸出列表的困境。我可能以錯誤的方式思考它，任何幫助我走向正確方向的幫助都是值得贊賞的。import mathp1 = input("please enter x1 and y1: ")p2 = input("please enter x2 and y2: ")x1y1 = p1.split(',')x2y2 = p2.split(',')distance = math.sqrt( ((x1y1[0]-x2y2[0])**2)+((x1y1[1]-x2y2[1])**2) )print(distance)
5 回答
鴻蒙傳說
TA貢獻1865條經驗 獲得超7個贊
您可以使用列表理解將輸入轉換為ints，然后進行解構賦值以將它們分配給兩個不同的變量：
from math import sqrt
[x1, y1] = [int(n) for n in input("please enter x1 and y1: ").split()]
[x2, y2] = [int(n) for n in input("please enter x2 and y2: ").split()]
print(f"Distance: {sqrt((x1-x2)**2+(y1-y2)**2)}")
偶然的你
TA貢獻1841條經驗 獲得超3個贊
首先將每個元素轉換為 int：
p1 = input("please enter x1 and y1: ")
p2 = input("please enter x2 and y2: ")
x1y1 = [int(x) for x in p1.split(',')]
x2y2 = [int(y) for y in p2.split(',')]
慕碼人8056858
TA貢獻1803條經驗 獲得超6個贊
這可以幫助：
from math import sqrt
xi, yi = [int(i) for i in input().split()]
xf, yf = [int(i) for i in input().split()]
print(math.sqrt((xf-xi)**2 + (yf-yi)**2))
守著一只汪
TA貢獻1872條經驗 獲得超4個贊
import math
p1 = input("please enter x1 and y1: ")
p2 = input("please enter x2 and y2: ")
x1y1 = [int(num) for num in p1.split(',')]
x2y2 = [int(num) for num in p2.split(',')]
distance = math.sqrt( ((x1y1[0]-x2y2[0])**2)+((x1y1[1]-x2y2[1])**2) )
print(distance)
Str 應轉換為 int。
心有法竹
TA貢獻1866條經驗 獲得超5個贊
您可以使用map()輕松轉換為int
import math
p1 = input("please enter x1 and y1: ")
p2 = input("please enter x2 and y2: ")
x1y1 = list(map(int, p1.split(',')))
x2y2 = list(map(int, p2.split(',')))
distance = math.sqrt( ((x1y1[0]-x2y2[0])**2)+((x1y1[1]-x2y2[1])**2) )
print(distance)
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