我正在嘗試編寫一個基本代碼，提示用戶輸入數字列表作為單獨的輸入，然后識別最大和最小的數字。如果用戶輸入數字以外的任何內容，代碼應返回“無效輸入”消息。該代碼似乎運行了兩個輸入一次，但隨后 while 輸入似乎完全損壞了，我不確定它出了什么問題。largest = Nonesmallest = Nonetry: num1 = input("Enter a number: ") num1 = int(num1) largest = num1 smallest = num1 while True: num = input("Enter a number: ") if num == "done" : break if num > largest: largest = num if num < smallest: smallest = num else: continueexcept: print('Invalid input')print("Maximum is ", largest)print("Minimum is ", smallest)
3 回答
浮云間
TA貢獻1829條經驗 獲得超4個贊
如果您檢查“完成”的退出條件并且輸入不是“完成”，則將字符串轉換為整數。然后所有 if 條件都會正確，并且您的 while 循環應該運行。
largest = None
smallest = None
try:
num1 = input("Enter a number: ")
num1 = int(num1)
largest = num1
smallest = num1
while True:
num = input("Enter a number: ")
if num == "done" :
break
num = int(num)
if num > largest:
largest = num
if num < smallest:
smallest = num
else: continue
except:
print('Invalid input')
print("Maximum is ", largest)
print("Minimum is ", smallest)
寶慕林4294392
TA貢獻2021條經驗 獲得超8個贊
這是一個簡單的方法：
lst = []
while True:
try:
lst.append(int(input("enter a number: ")))
except:
break
print(f"max is {max(lst)}")
print(f"min is {min(lst)}")
enter a number: 10
enter a number: 22
enter a number: 11
enter a number: 22
enter a number: 4
enter a number: done
max is 22
min is 4
繁星淼淼
TA貢獻1775條經驗 獲得超11個贊
除了其他更正之外：
largest = None
smallest = None
try:
num1 = int(input("Enter a number: "))
largest = num1
smallest = num1
while True:
num = input("Enter a number: ")
if str(num) == "done" :
break
if int(num) > largest:
largest = num
if int(num) < smallest:
smallest = num
else: continue
except:
print('Invalid input')
print("Maximum is ", largest)
print("Minimum is ", smallest)
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