IP范圍10.0.0.1-10.0.0.3可擴展至10.0.0.110.0.0.210.0.0.3通過使用這個腳本eval printf '%s\\n' $(echo '10.0.0.1-10.0.0.3' | awk -F'[.-]' -v OFS='.' '{for(i=1;i<=4;i++) $i = "{" $i ".." $(i+4) "}"; NF=4} 1')但如果我有一組這樣的數據；10.0.0.1-10.0.0.3172.16.0.3192.168.0.2-192.168.0.2我如何產生這樣的輸出？10.0.0.110.0.0.210.0.0.3172.16.0.3192.168.0.2
1 回答
天涯盡頭無女友
TA貢獻1831條經驗 獲得超9個贊
您能否嘗試以下操作，僅在 GNU 中使用所示示例進行編寫和測試awk。
awk '
BEGIN{
FS="-"
OFS="."
}
$1==$2 || NF==1{
print $1
next
}
{
num1=split($1,arr1,".")
num2=split($2,arr2,".")
for(i=arr1[num1];i<=arr2[num2];i++){
print arr1[1],arr1[2],arr1[3],i
}
}' Input_file
說明：對上述內容添加詳細說明。
awk ' ##Starting awk program from here.
BEGIN{ ##Starting BEGIN section of this program from here.
FS="-" ##Setting field separator as - here.
OFS="." ##Setting output field separator as . here.
}
$1==$2 || NF==1{ ##Checking condition if 1st field is equal to 2nd field OR number of fields is 1 then do following.
print $1 ##Printing 1st field of current line here.
next ##next will skip all further statements from here.
}
{
num1=split($1,arr1,".") ##Splitting $1 into arr1 with delimiter . AND num1 will have total number of elements in arr1.
num2=split($2,arr2,".") ##Splitting $2 into arr2 with delimiter . AND num2 will have total number of elements in arr1.
for(i=arr1[num1];i<=arr2[num2];i++){ ##Running for loop from last value of 1st field to last value of 2nd field.
print arr1[1],arr1[2],arr1[3],i ##Printing arr1 1st, 2nd and 3rd value and then printing value of i here.
}
}' Input_file ##Mentioning Input_file name here.
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