這就是我目前擁有的：messages = { "Placeholder": 0, "1": 48, "2": 4, "3": 31, "4": 2}def pls(): messages_sorted = sorted(messages, key=messages.get, reverse=True) for i in range(10): output = [] try: currp = str(messages_sorted[i]) if currp == "Placeholder": print("PLACEHOLDER DETECTED") return output currpp = messages[currp] output.append(f"{currp} has {currpp} and is Place {i+1}") print(output) except IndexError: print("Index error") except: print("some other error") return outputoutput = pls()output = str(output)output = output.replace("['", "")output = output.replace("']", "")print(output)我已經使用這個問題的答案將不同的輸出制作為一個列表，但是當我運行它時，它返回一個空列表。當我刪除以下部分時：if currp == "Placeholder": print("PLACEHOLDER DETECTED") return output我剛剛收到一堆索引錯誤。這print(output)在 for 循環內部，我得到了控制臺中所需的內容（作為不同的字符串），但是我無法將其作為 List 或變量返回。我怎樣才能做到這一點？
2 回答
慕桂英3389331
TA貢獻2036條經驗 獲得超8個贊
當您返回時，您的output列表是空的，因為每次for loop重新啟動時都會重置列表。
您的代碼應如下所示：
messages = {
"Placeholder": 0,
"1": 48,
"2": 4,
"3": 31,
"4": 2
}
def pls():
messages_sorted = sorted(messages, key=messages.get, reverse=True)
output = []
for i in range(10):
try:
currp = str(messages_sorted[i])
if currp == "Placeholder":
print("PLACEHOLDER DETECTED")
return output
currpp = messages[currp]
output.append(f"{currp} has {currpp} and is Place {i+1}")
print(output)
except IndexError:
print("Index error")
except:
print("some other error")
return output
output = pls()
output = str(output)
output = output.replace("['", "")
output = output.replace("']", "")
print(output)
添加回答
舉報
0/150
提交
取消