我從 API 獲取 JSON 數據。數據集很大并且是嵌套的。我可以Datenreihen這樣訪問密鑰：jsondata.get("Ergebnis")[0].get("Kontakte").get("Datenreihen")正如您所看到的，這是字典和列表的混合體。我嘗試了以下方法，但對于列表不起作用:-(。def recursive_lookup(k, d): if k in d: return d[k] for v in d.values(): if isinstance(v, dict): return recursive_lookup(k, v) return None# Worksrecursive_lookup("Ergebnis", jsondata)# Returns Nonerecursive_lookup("Datenreihen", jsondata)無論我的對象嵌套多深，是否有一種簡單的方法可以訪問和鍵入我的字典？這是示例數據：{ "Success":true, "Ergebnis":[ { "ErgA1a: KPI Zeitreihe":{ "Message":"", "MitZielgruppe":true, "Beschriftung":[ "2019 KW 27", "2019 KW 28", "2019 KW 29" ], "Datenreihen":{ "Gesamt":{ "Name":"Sympathie [#4]\n(Sehr sympathisch, Sympathisch)", "Werte":[ 39.922142815641145, 37.751410794385762, 38.35504885993484 ] } } } } ], "rest":[ { "test":"bla" } ] } data.get("ErgebnisseAnalyse")[0].get("ErgA1a: KPI Zeitreihe")recursive_lookup("ErgA1a: KPI Zeitreihe", data)
1 回答
茅侃侃
TA貢獻1842條經驗 獲得超21個贊
遞歸函數根據鍵字段在嵌套字典中查找值
代碼
def find_item(obj, field):
"""
Takes a dict with nested lists and dicts,
and searches all dicts for a key of the field
provided.
"""
if isinstance(obj, dict):
for k, v in obj.items():
if k == field:
yield v
elif isinstance(v, dict) or isinstance(v, list):
yield from find_item(v, field)
elif isinstance(obj, list):
for v in obj:
yield from find_item(v, field)
用法
value = next(find_item(dictionary_object, field), None)
測試
# Nested dictionary
dic = {
"a": [{"b": {"c": 1}},
{"d": 2}],
"e": 3}
# Values form various fields
print(next(find_item(dic, "a"), None)) # Output: [{'b': {'c': 1}}, {'d': 2}]
print(next(find_item(dic, "b"), None)) # Output: {'c': 1}
print(next(find_item(dic, "c"), None)) # Output: 1
print(next(find_item(dic, "d"), None)) # Output: 2
print(next(find_item(dic, "e"), None)) # Output: 3
print(next(find_item(dic, "h"), None)) # Output: None
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