我有以下字符串，我想A1用列表中的每個字符替換befcodes并打印它：befcodes = ["A1","A2","A3","A4","A5","A6","A7","A8","A9","10","11","12","13","14","15","16","17","18","19","20"]telegram = "$00;02;A1;00000000*49"我想得到如下所示的輸出：$00;02;A1;00000000*49$00;02;A2;00000000*49$00;02;A3;00000000*49......$00;02;19;00000000*49$00;02;20;00000000*49我嘗試了幾種不同的字符串格式化和 for 循環方法，但沒有完全掌握它的竅門。你們能幫我一下嗎？
1 回答
米脂
TA貢獻1836條經驗 獲得超3個贊
你應該使用str.replace
befcodes = ["A1", "A2", "A3", "A4", "A5", "A6", "A7", "A8", "A9",
"10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "20"]
telegram = "$00;02;A1;00000000*49"
for code in befcodes:
print(telegram.replace("A1", code))
給予
$00;02;A1;00000000*49
$00;02;A2;00000000*49
$00;02;A3;00000000*49
...
$00;02;18;00000000*49
$00;02;19;00000000*49
$00;02;20;00000000*49
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