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如何在 JavaScript 中刪除空白數組

如何在 JavaScript 中刪除空白數組

慕容708150 2023-11-02 17:15:21
我是 JavaScript 新手。初始數據:["Argentina", "Maroon 5:50<br>"]["Australia", "Maroon 5:224<br>"]["Austria", "Maroon 5:42<br>"]["Belgium", "Maroon 5:10<br>"][""]["Brazil", "Maroon 5:187<br>"][""]["Canada", "Maroon 5:160<br>"][""]["China", "Maroon 5:10<br>"][""][""][""][""][""][""][""][""]["France", "Maroon 5:1533<br>"]我的代碼:     $.each(resp.result.artists_detail, function(index, item) {  var arr = [];  var pop_val = [];                         var artistdetails="";  for (var i = 0; i < resp.result.artists.length; i++) {    arr.push(item[0].country_name);    if(item[i].play_count != 0){      artistdetails +=item[i].artist_name +':'+ item[i].play_count+'<br>';    }else{      arr.pop(artistdetails);    }    }  arr.push(artistdetails);  arrOfChart.push(arr);});我需要這個結果:["Argentina", "Maroon 5:50<br>"]["Australia", "Maroon 5:224<br>"]["Austria", "Maroon 5:42<br>"]["Belgium", "Maroon 5:10<br>"]["Brazil", "Maroon 5:187<br>"]["Canada", "Maroon 5:160<br>"]["China", "Maroon 5:10<br>"]["France", "Maroon 5:1533<br>"]如何刪除空白數組?我正在嘗試為數組推送添加數組并為數組彈出刪除數組,但我需要一個沒有空白數組的數組。
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4 回答

?
慕仙森

TA貢獻1827條經驗 獲得超8個贊

最后做:


arrOfChart = arrOfChart.filter(arr=>!(arr.length == 1 && arr[0] == ""))

console.log(arrOfChart)

>>>[

["Argentina", "Maroon 5:50<br>"],

["Australia", "Maroon 5:224<br>"],

["Austria", "Maroon 5:42<br>"],

["Belgium", "Maroon 5:10<br>"],

["Brazil", "Maroon 5:187<br>"],

["Canada", "Maroon 5:160<br>"],

["China", "Maroon 5:10<br>"],

["France", "Maroon 5:1533<br>"]

]


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?
慕蓋茨4494581

TA貢獻1850條經驗 獲得超11個贊

要從數組中刪除空值,您需要使用filter函數:


var array = [0, 1, null, 2, "", 3, undefined, 3,,,,,, 4,, 4,, 5,, 6,,,,];


var filtered = array.filter(function (el) {

  return el != "";

});


console.log(filtered);


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?
皈依舞

TA貢獻1851條經驗 獲得超3個贊

你只需使用filter


let data = [["Argentina", "Maroon 5:50<br>"],

["Australia", "Maroon 5:224<br>"],

["Austria", "Maroon 5:42<br>"],

["Belgium", "Maroon 5:10<br>"],

[""],

["Brazil", "Maroon 5:187<br>"],

[""],

["Canada", "Maroon 5:160<br>"],

[""],

["China", "Maroon 5:10<br>"],

[""],

[""],

[""],

[""],

[""],

[""],

[""],

[""],

["France", "Maroon 5:1533<br>"]]


let result = data.filter(([el]) => el);


console.log(result);


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?
胡子哥哥

TA貢獻1825條經驗 獲得超6個贊

通過使用( to ).filter的隱式強制,您可以實現這一點""false


baseArray.filter( subArray => subArray[0]);

const baseArray = [["Argentina", "Maroon 5:50<br>"],

["Australia", "Maroon 5:224<br>"],

["Austria", "Maroon 5:42<br>"],

["Belgium", "Maroon 5:10<br>"],

[""],

["Brazil", "Maroon 5:187<br>"],

[""],

["Canada", "Maroon 5:160<br>"],

[""],

["China", "Maroon 5:10<br>"],

[""],

[""],

[""],

[""],

[""],

[""],

[""],

[""],

["France", "Maroon 5:1533<br>"]

];


const result = baseArray.filter( subArray => subArray[0]);


console.log(result);


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