我收到 ButtonClick 方法內任何函數的屬性錯誤。請幫助糾正這個問題。import tkinter as tkfrom tkinter import *root = tk.Tk()enter = tk.Entry(root, width = 35, borderwidth = 5).grid(row = 0, column = 0, columnspan = 3, padx =10 , pady = 10)def ButtonClick(number): print(number) current = enter.get() print(current) # enter.delete(0,END) # enter.insert(0, current + number)button1 = tk.Button(root, text="1", bg="yellow",padx = 40, pady= 20, command=lambda: ButtonClick(1)).grid(row = 1, column = 0)root.mainloop()
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TA貢獻1810條經驗 獲得超5個贊
python shell 使實驗變得很容易。假設錯誤是因為enter我剛剛將代碼的第一部分粘貼到 shell 中。
>>> import tkinter as tk
>>> from tkinter import *
>>>
>>> root = tk.Tk()
>>>
>>> enter = tk.Entry(root, width = 35, borderwidth = 5).grid(row = 0, column = 0, columnspan = 3, padx =10 , pady = 10)
>>> repr(enter)
'None'
是的，它的None。這是典型的。對象方法通常不返回自己的對象。它對于方法鏈接很方便，但大多數對象并不是為此而設計的。只需按照示例和教程所示操作即可，并將其放在單獨的行中。
import tkinter as tk
from tkinter import *
root = tk.Tk()
enter = tk.Entry(root, width = 35, borderwidth = 5)
enter.grid(row = 0, column = 0, columnspan = 3, padx =10 , pady = 10)
def ButtonClick(number):
print(number)
current = enter.get()
print(current)
# enter.delete(0,END)
# enter.insert(0, current + number)
button1 = tk.Button(root, text="1", bg="yellow",padx = 40, pady= 20, command=lambda: ButtonClick(1)).grid(row = 1, column = 0)
root.mainloop()
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