我創建了一個 python 劊子手游戲，除了一個與計算失敗嘗試次數相關的邏輯錯誤外，它運行良好。 failed = 0 for char in word: if char in letter_guess: print(char, end="") if letter_guess == word: print("") print('CONGRATULATIONS! YOU WON') sys.exit() else: failed = failed + 1 print('_ ', end="") if failed == 15: print("GAME OVER! your word was", word) sys.exit() 當玩家猜錯一個字母時，它不是只添加一個，而是為每個不是玩家猜到的字母的字母添加一個。例如，如果單詞是“star”，而玩家猜到了字母“e”，那么程序將添加 4 表示失??；每個字母一個。我不知道如何解決這個問題，以便它只執行一次這個特定的功能，因為我仍然需要它為每個錯誤的字母添加一個“_”。我想也許我可以將 4 個字母單詞的嘗試次數乘以 4，但我不確定這是否有效。這是完整的代碼import randomimport timeimport sys# GAME INTRODUCTIONprint('HANGMAN')name = input('Username: ')print('Welcome', name, 'are you ready to play?')answer = ''print("type 'start' to begin")while answer != 'start': time.sleep(0.7) answer = input()print("OK! Let's begin")print("pick the mode/difficulty of the game")time.sleep(0.7)print("1-Easy")print("2-Medium")print("3-Difficult")# POSSIBLE WORDS IN GAMEwords_4 = ['time', 'king', 'song', 'disk', 'meal', 'cell', 'hair', 'menu', 'math']words_5 = ['world', 'paper', 'hotel', 'queen', 'uncle', 'night', 'hotel', 'shirt', 'pizza']words_6 = ['person', 'tennis', 'camera', 'sector', 'potato', 'safety', 'growth', 'thanks']# CHOOSING GAME DIFFICULTYmode = str(input())if mode in ['Easy', '1', 'easy']: word_list = words_4 letter_num = 4 print("your word consists of 4 letters")elif mode in ['Medium', '2', 'medium']: word_list = words_5 letter_num = 5 print("your word consists of 5 letters")elif mode in ['Difficult', '3', 'difficult']: word_list = words_6 letter_num = 6 print("your word consists of 6 letters")else: print("Mode does not exist!")
3 回答
慕俠2389804
TA貢獻1719條經驗 獲得超6個贊
您的代碼中有幾個問題。
玩家永遠不會獲勝，因為
letter_guess == word只有當該單詞只有一個字母或用戶每輪能夠輸入多個字母時才為真，我不認為這是這里的想法。在失敗中，您不是在計算嘗試次數，而是在計算丟失的字母。換句話說，您在每次嘗試中都在計算“_”。
我將在這里為您留下一些固定的代碼，以便您可以將其用作參考：
我創建了一個 python 劊子手游戲，除了一個與計算失敗嘗試次數相關的邏輯錯誤外，它運行良好。
failed = 0
for char in word:
if char in letter_guess:
print(char, end="")
if letter_guess == word:
print("")
print('CONGRATULATIONS! YOU WON')
sys.exit()
else:
failed = failed + 1
print('_ ', end="")
if failed == 15:
print("GAME OVER! your word was", word)
sys.exit()
當玩家猜錯一個字母時，它不是只添加一個，而是為每個不是玩家猜到的字母的字母添加一個。例如，如果單詞是“star”，而玩家猜到了字母“e”，那么程序將添加 4 表示失??；每個字母一個。我不知道如何解決這個問題，以便它只執行一次這個特定的功能，因為我仍然需要它為每個錯誤的字母添加一個“_”。我想也許我可以將 4 個字母單詞的嘗試次數乘以 4，但我不確定這是否有效。
這是完整的代碼
import random
import time
import sys
# GAME INTRODUCTION
print('HANGMAN')
name = input('Username: ')
print('Welcome', name, 'are you ready to play?')
answer = ''
print("type 'start' to begin")
while answer != 'start':
time.sleep(0.7)
answer = input()
print("OK! Let's begin")
print("pick the mode/difficulty of the game")
time.sleep(0.7)
print("1-Easy")
print("2-Medium")
print("3-Difficult")
# POSSIBLE WORDS IN GAME
words_4 = ['time', 'king', 'song', 'disk', 'meal',
'cell', 'hair', 'menu', 'math']
words_5 = ['world', 'paper', 'hotel', 'queen', 'uncle',
'night', 'hotel', 'shirt', 'pizza']
words_6 = ['person', 'tennis', 'camera', 'sector',
'potato', 'safety', 'growth', 'thanks']
# CHOOSING GAME DIFFICULTY
mode = str(input())
if mode in ['Easy', '1', 'easy']:
word_list = words_4
letter_num = 4
print("your word consists of 4 letters")
elif mode in ['Medium', '2', 'medium']:
word_list = words_5
letter_num = 5
print("your word consists of 5 letters")
elif mode in ['Difficult', '3', 'difficult']:
word_list = words_6
letter_num = 6
print("your word consists of 6 letters")
else:
print("Mode does not exist!")
number = 0
i = 0
dash = ('_ ')
word = random.choice(word_list)
for char in word:
i = i + 1
for number in range(i):
print(dash, end="")
failed = 0
guessed = ('')
print("")
#CHECKING CHARACTER PLAYER INPUTTED
tries = True
while tries is True:
print("")
print("")
letter_guess = input('Guess any letter: ')
for char in word:
if char in letter_guess:
print(char, end="")
if letter_guess == word:
print("")
print('CONGRATULATIONS! YOU WON')
sys.exit()
else:
print('_ ', end="")
if failed == 15:
print("GAME OVER! your word was", word)
sys.exit()
Pythonpython-3.x
藍山帝景
TA貢獻1843條經驗 獲得超7個贊
我對您的代碼做了一些小更改，而不是增加失敗的循環，您必須將其放在循環之外for，但仍然在while循環內部。
并且您需要將其放在循環sys.exit()外部while，因為您使用，如果字母猜測全部正確，則while Tries is True可以將其放在循環Tries = False內部，如果 , 則可以將 1 放在循環外部forforfailure = 15
希望這是你想要達到的目標
tries = True
while tries is True:
print("")
print("")
letter_guess = input('Guess any letter: ')
is_failed = False
for char in word:
if char in letter_guess:
print(char, end="")
if letter_guess == word:
print("")
print('CONGRATULATIONS! YOU WON')
tries = False
break
else:
is_failed = True
print('_ ', end="")
if is_failed:
failed = failed + 1
is_failed = False
if failed == 15:
print('')
print('')
print("GAME OVER! your word was", word)
tries = False
sys.exit()
如果您想存儲以前的答案，并使您的代碼更簡潔：
tries = True
guessed_word = ['_' for _ in range(len(word))]
while tries is True:
print("")
print("")
letter_guess = input('Guess any letter: ')
is_failed = False
for i, char in enumerate(word):
if char in letter_guess:
guessed_word[i] = char
else:
is_failed = True
print(' '.join(guessed_word))
if is_failed:
failed = failed + 1
is_failed = False
if failed == 15:
print('')
print("GAME OVER! your word was", word)
tries = False
if '_' not in guessed_word:
print("")
print('CONGRATULATIONS! YOU WON')
tries = False
sys.exit()
婷婷同學_
TA貢獻1844條經驗 獲得超8個贊
我對您的代碼做了一些小更改，而不是增加失敗的循環，您必須將其放在循環之外for，但仍然在while循環內部。
并且您需要將其放在循環sys.exit()外部while，因為您使用，如果字母猜測全部正確，則while Tries is True可以將其放在循環Tries = False內部，如果 , 則可以將 1 放在循環外部forforfailure = 15
希望這是你想要達到的目標
tries = True
while tries is True:
print("")
print("")
letter_guess = input('Guess any letter: ')
is_failed = False
for char in word:
if char in letter_guess:
print(char, end="")
if letter_guess == word:
print("")
print('CONGRATULATIONS! YOU WON')
tries = False
break
else:
is_failed = True
print('_ ', end="")
if is_failed:
failed = failed + 1
is_failed = False
if failed == 15:
print('')
print('')
print("GAME OVER! your word was", word)
tries = False
sys.exit()
如果您想存儲以前的答案，并使您的代碼更簡潔：
tries = True
guessed_word = ['_' for _ in range(len(word))]
while tries is True:
print("")
print("")
letter_guess = input('Guess any letter: ')
is_failed = False
for i, char in enumerate(word):
if char in letter_guess:
guessed_word[i] = char
else:
is_failed = True
print(' '.join(guessed_word))
if is_failed:
failed = failed + 1
is_failed = False
if failed == 15:
print('')
print("GAME OVER! your word was", word)
tries = False
if '_' not in guessed_word:
print("")
print('CONGRATULATIONS! YOU WON')
tries = False
sys.exit()
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