<?php$pdo = new PDO("mysql:dbname=sample;host=localhost", "admin", "passwd"); $statement = $pdo->prepare("SELECT first_name, last_name FROM accounts WHERE account_id='1'");$statement->execute();$results = $statement->fetchAll(PDO::FETCH_ASSOC);$json = json_encode($results);echo "$json";?>結果是[{"first_name":"John","last_name":"Doe"}]使用 javascript 的預期結果：John Doe
1 回答
陪伴而非守候
TA貢獻1757條經驗 獲得超8個贊
作為評論中的 json 代碼，您可以執行以下操作：
var obj = JSON.parse('[{"first_name":"john","last_name":"doe"},{"first_name":"Jeen","last_name":"dra"},{"first_name":"Ad","last_name":"Does"},{"first_name":"Arin","last_name":"Gan"},{"first_name":"Jason","last_name":"Ford"},{"first_name":"Prince","last_name":"addar"},{"first_name":"Derek","last_name":"Frenzi"},{"first_name":"Jay","last_name":"dar"},{"first_name":"dam","last_name":"guly"},{"first_name":"nita","last_name":"Sa"}]');
for (i=0 ; i<obj.length ; i++){
document.getElementById("demo").innerHTML += obj[i].first_name + " " + obj[i].last_name + "<br>" ;
}
- 1 回答
- 0 關注
- 182 瀏覽
添加回答
舉報
0/150
提交
取消