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有沒有一種不太奇怪的方法來生成這個虛擬數據?

有沒有一種不太奇怪的方法來生成這個虛擬數據?

30秒到達戰場 2023-10-18 16:07:49
輸入:word_types 列表,例如 ["verb", "adjective", "name", "noun]期望的輸出:按 word_type 排列的每個字母-word_type 組合的三個單詞的字典。IE{“動詞”:[“Averb1”,“Averb2”,“Averb3”],[Bverb1,...],...,“形容詞”:[“Aadjective1”,“Aadjectives2”,“Aadjectives3”] .. 。 ETC這是我用來生成數據的內容。import stringA_to_Z = list(string.ascii_uppercase)  #  list of letters a-zlettered_word_types = ["verb", "adjective", "name", "noun"]class Lexicon:    def __init__(self, testing = True):        if testing == True:            for TYPE in lettered_word_types:                setattr(self, TYPE + "s", [letter + TYPE for letter in A_to_Z])        self.__dict__ = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in self.__dict__.items()}data = Lexicon().__dict__
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冉冉說

TA貢獻1877條經驗 獲得超1個贊

該類沒有任何作用,它只是混淆了你正在做的事情。要將代碼音譯為dict直接使用 a,您只需要:


result = {}

for TYPE in lettered_word_types:

    result[TYPE + 's'] = [letter + TYPE for letter in A_to_Z]

result = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in result.items()}

所以,只是為了證明這確實是等價的:


In [1]: import string

    ...: A_to_Z = list(string.ascii_uppercase)  #  list of letters a-z

    ...: lettered_word_types = ["verb", "adjective", "name", "noun"]

    ...:

    ...: class Lexicon:

    ...:     def __init__(self, testing = True):

    ...:         if testing == True:

    ...:             for TYPE in lettered_word_types:

    ...:                 setattr(self, TYPE + "s", [letter + TYPE for letter in A_to_Z])

    ...:         self.__dict__ = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in self.__dict__.items()}

    ...:

    ...:

    ...: data = Lexicon().__dict__


In [2]: result = {}


In [3]: for TYPE in lettered_word_types:

    ...:     result[TYPE + 's'] = [letter + TYPE for letter in A_to_Z]

    ...:


In [4]: result = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in result.items()}


In [5]: result == data

Out[5]: True


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