我正在使用 XAMPP，我想從數據庫表中選擇一個隨機記錄并通過電子郵件發送。我正在使用測試郵件服務器工具，但收到下一個錯誤：警告：mail()：第 24 行 C:\xampp\htdocs\dailyapp\sender2.php 中的錯誤消息返回路徑 糟糕！出了點問題，我們無法發送您的消息。這里可能發生什么？任何想法？PHP代碼：<?php$servername = "localhost";$username = "root";$password = "";$dbname = "dapp";// Create connection$conn = new mysqli($servername, $username, $password, $dbname);// Check connectionif ($conn->connect_error) {  die("Connection failed: " . $conn->connect_error);}$recipient = "[email protected]";$sql = "SELECT * FROM my_messages ORDER BY RAND() LIMIT 1";$result = $conn->query($sql);if ($result->num_rows > 0) {    ($row = $result->fetch_assoc());    $subject = $row["subject"];    $message = $row["message"];        if (mail($recipient, $subject, $message)) {        http_response_code(200);        echo "All good";    }        else {        http_response_code(500);        echo "Oops! Something went wrong and we couldn't send your message.";        }}    else {    echo 0;};?>