我侄女在學校做作業時問我這個問題，我不知道該怎么做。老師要求他們在 java 中使用 3 個 for 循環打印以下模式：1******12*****123****1234***12345**123456*1234567請幫忙。謝謝！
3 回答
慕蓋茨4494581
TA貢獻1850條經驗 獲得超11個贊
這曾經是我的家庭作業
代碼
for (int i = 1; i <= 7; i++) {
for (int j = 1; j <= i; ++j) {
System.out.print(j);
}
System.out.println("");
}
將會呈現
1
12
123
1234
12345
123456
1234567
和
for (int i = 1; i <= 7; i++) {
for (int k = 7 - i; k >= 1; k--) {
System.out.print("*");
}
System.out.println("");
}
將會呈現
******
*****
****
***
**
*
最終的
for (int i = 1; i <= 7; i++) {
for (int j = 1; j <= i; ++j) {
System.out.print(j);
}
for (int k = 7 - i; k >= 1; k--) {
System.out.print("*");
}
System.out.println("");
}
將會呈現
1******
12*****
123****
1234***
12345**
123456*
1234567
回首憶惘然
TA貢獻1847條經驗 獲得超11個贊
public static void printPattern(int n) {
for(int i=0; i<n; i++) {
for(int k=1; k<=i+1; k++) {
System.out.print(k);
}
for(int j=i+1; j<n; j++) {
System.out.print("*");
}
System.out.println("");
}
}
MYYA
TA貢獻1868條經驗 獲得超4個贊
Are you sure question has been asked to solve by using 3 for loops?
As it is better to use less loop as much as we can. Secondly there is no requirement in problem to use third loop. you can find the desired result by using two loops:
public class Main
{
public static void main(String[] args) {
for (int i = 1; i <= 7; i++) {
for (int j = 1; j <= 7; j++) {
if (j <= i) {
System.out.print(j);
}
else
{
System.out.print("*");
}
}
System.out.println("\n");
}
}
}
output will be:
1******
12*****
123****
1234***
12345**
123456*
1234567
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