首頁猿問從 XML 中刪除所有出現的特定屬性

從 XML 中刪除所有出現的特定屬性

Java

慕田峪7331174 2023-10-12 14:38:06

我有一個 XML 文件，內容如下<document> <section> <section SectionName="abstract"> <paragraph> <word Endpoint="1" SciomeSRIE_Sentence.ExposureSentence="1">gutkha</word> <word ExposureSentence="1">split_identifier ,</word> <word ExposureSentence="1">and</word> <word ExposureSentence="1">what</word> <word ExposureSentence="1">role</word> <word ExposureSentence="1">split_identifier ,</word> <word ExposureSentence="1">if</word> <word ExposureSentence="1">any</word> <word ExposureSentence="1">split_identifier ,</word> <word ExposureSentence="1">nicotine</word> <word ExposureSentence="1">contributes</word> <word ExposureSentence="1">to</word> <word ExposureSentence="1">the</word> <word ExposureSentence="1">effects</word> <word ExposureSentence="1">split_identifier .</word> <word EB_NLP_Tagger.Participant="3" AnimalGroupSentence="1" DoseGroupSentence="1" ExposureSentence="2">Adult</word> <word EB_NLP_Tagger.Participant="3" Sex="1" AnimalGroupSentence="1" DoseGroupSentence="1" ExposureSentence="2">male</word> <word EB_NLP_Tagger.Participant="3" Species="1" AnimalGroupSentence="1" DoseGroupSentence="1" ExposureSentence="2">mice</word> <word AnimalGroupSentence="1" DoseGroupSentence="1" ExposureSentence="2">were</word> <word AnimalGroupSentence="1" DoseGroupSentence="1" ExposureSentence="2">treated</word> <word AnimalGroupSentence="1" DoseGroupSentence="1" ExposureSentence="2">daily</word> <word AnimalGroupSentence="1" DoseGroupSentence="1" ExposureSentence="2">for</word>

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2 回答

慕標5832272

TA貢獻1966條經驗獲得超4個贊

XPath 使這變得簡單：

public static void main(String... args)

throws Exception

{

DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();

DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();

Document doc = dBuilder.parse(new ByteArrayInputStream(xml.getBytes()));

XPathFactory xPathfactory = XPathFactory.newInstance();

XPath xpath = xPathfactory.newXPath();

// Find word elements with ExposureSentence attribute

XPathExpression query = xpath.compile("//word[@ExposureSentence]");

NodeList words = (NodeList) query.evaluate(doc, XPathConstants.NODESET);

for (int i = 0; i < words.getLength(); i++) {

// Remove the attribute

((Element) words.item(i)).removeAttribute("ExposureSentence");

}

// Handle ComponentName

query = xpath.compile("//ComponentName");

NodeList componentNames = (NodeList) query.evaluate(doc, XPathConstants.NODESET);

for (int i = 0; i < componentNames.getLength(); i++) {

String content = componentNames.item(i).getTextContent();

componentNames.item(i).setTextContent(

Arrays.stream(content.split(","))

.map(String::trim)

.filter(s -> !s.equals("ExposureSentence"))

.collect(Collectors.joining(", ")));

}

// Omitted: Save the XML

}

反對回復 2023-10-12

元芳怎么了

TA貢獻1798條經驗獲得超7個贊

我認為最簡單的解決方案是ExposureSentence="1"使用簡單的正則表達式替換所有出現的情況。將所有 xml 內容讀取為 String，并替換所有不需要 XML 解析和替換的特定單詞出現位置。

在 XML 解析的情況下，您需要解析、操作邏輯，并且必須重建 XML 信息集。

反對回復 2023-10-12

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從 XML 中刪除所有出現的特定屬性

從 XML 中刪除所有出現的特定屬性

2 回答

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