我有兩個 python 列表。A= ['today is sunday', 'today is wednesday']B= ['today is sunday', 'today is Monday'....'today is Saturday'] For elm in A: If elm in B: print ("not ok") else: print ("ok")我想計算兩個 python 列表之間元素匹配的百分比。所需的匹配百分比計算如圖所示：
2 回答
月關寶盒
TA貢獻1772條經驗 獲得超5個贊
有可能 ：
A= ['today is sunday', 'today is wednesday']
B= ['today is sunday', 'today is monday', 'today is Saturday']
match_percent = (len(set(B).intersection(set(A))))/len(B)*100
print(match_percent)
互換的青春
TA貢獻1797條經驗 獲得超6個贊
我不確定您想要計算的確切匹配百分比，因此我冒昧地計算為match_count / max(list_a_size, list_b_size)。
def intersection(lst1, lst2):
lst3 = [value for value in lst1 if value in lst2]
return len(lst3)
def maximum(a, b):
if a >= b:
return a
else:
return b
A= ['today is sunday', 'today is wednesday']
B= ['today is sunday', 'today is Monday', 'today is Saturday']
match_percent = intersection(A, B) / maximum(len(A),len(B))
print(match_percent)
輸出：
0.3333333333333333
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