如果兩個數組包含相同數量的項目，那么您可以使用普通的 for 循環來訪問具有相同索引的每個項目，如下所示 -let home_team = ["A", "B", "C"];let away_team = ["D", "E", "F"];for(let i=0; i<home_team.length; i++){ console.log(`${home_team[i]} VS ${away_team[i]}`);}展開片段或者，您也可以在 for 循環中使用多個計數器，如下所示（盡管您現在不需要這個 -let home_team = ["A", "B", "C"];let away_team = ["D", "E", "F"];for(let i=0,j=2; i<home_team.length; i++, j--){ console.log(`${home_team[i]} VS ${away_team[j]}`);}
如何防止直接在js/ts類中更新屬性？
子衿沉夜
2023-09-28 16:07:04
