我已經實現了一個程序，它接受一個列表，并根據前一個、當前和下一個元素返回唯一值。但是，當列表開頭有兩個以上相同元素時，該程序將不起作用。前任：[0, 0, 0, 1]這是代碼，后面是機制的描述。def test(current): iterator = iter(current) previous_item = next(iterator) current_item = next(iterator) next_item = True while next_item: try: next_item = next(iterator) except StopIteration: next_item = None if previous_item == current_item: current_item = next_item else: yield previous_item previous_item = current_item current_item = next_item if previous_item: yield previous_item if __name__ == "__main__": l = [0, 0, 1, 2] for u in test(l): print(u)next_item如果是，則循環終止None。我只產生一個previous_itemif previous_itemis not equal to current_item。如果不等于，我也只移動previous_item“指針” ?？偸潜ＷC有一個值，所以我很困惑為什么諸如此類的輸入不會產生任何結果。previous_itemcurrent_itemprevious_item[0, 0, 0, 1]
1 回答
一只名叫tom的貓
TA貢獻1906條經驗 獲得超3個贊
你的 while 循環正在測試是否next_item不為 null，意思是不等于0、None、[]、{}等...所以一旦該值取 0，循環就會停止。
相反，你可以這樣做：
def test(current):
? ??
? ? iterator = iter(current)
? ? previous_item = next(iterator)
? ? current_item = next(iterator)
? ? next_item = 0
? ??
? ??
? ? while next_item is not None:
? ? ? ??
? ? ? ? try:
? ? ? ? ? ? next_item = next(iterator)? ? ? ?
? ? ? ? except StopIteration:
? ? ? ? ? ? next_item = None? ? ??
? ? ? ??
? ? ? ? if previous_item == current_item:
? ? ? ? ? ? current_item = next_item
? ? ? ? else:
? ? ? ? ? ? yield previous_item
? ? ? ? ? ? previous_item = current_item
? ? ? ? ? ? current_item = next_item
? ? ? ??
? ? if previous_item:
? ? ? ? yield previous_item
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