有人可以告訴我為什么該<?php echo $userPasswordError; ?>行不返回任何內容（空），而不是<div class="invalid-feedback">Too long.</div>當我使用以下代碼輸入包含超過 1 個字符的密碼時？如果我改變這一行：$userPasswordError = '<div class="invalid-feedback">Too long.</div>';有了這個$userPasswordError = 'Too long.';，就可以了！輸出是“太長”。<?php$user = $userPassword = '';$userError = $userInvalid = $userPasswordError = $userPasswordInvalid = '';$isvalidOrInvalidUser = $isvalidOrInvalidUserPassword = '';if ($_SERVER["REQUEST_METHOD"] == "POST") { // Verify username. if (!empty($_POST["user"])) { if (strlen($_POST["user"]) <= 32) { $user = $_POST["user"]; $userError = '<div class="valid-feedback">Correct.</div>'; $isvalidOrInvalidUser = 'is-valid'; } else { $userInvalid = $_POST["user"]; $userError = '<div class="invalid-feedback">Too long.</div>'; $isvalidOrInvalidUser = 'is-invalid'; } } else { $userError = '<div class="invalid-feedback">Please, add username.</div>'; $isvalidOrInvalidUser = 'is-invalid'; } // Verify password. if (!empty($_POST["userpassword"])) { if (strlen($_POST["userpassword"]) <= 1) { $userPassword = $_POST["userpassword"]; $userPasswordError = '<div class="valid-feedback">Correct.</div>'; $isvalidOrInvalidUserPassword = 'is-valid'; } else { $userPasswordInvalid = $_POST["userpassword"]; $userPasswordError = '<div class="invalid-feedback">Too long.</div>'; $isvalidOrInvalidUserPasword = 'is-invalid'; } } else { $userPasswordError = '<div class="invalid-feedback">Please, add password.</div>'; $isvalidOrInvalidUserPassword = 'is-invalid'; }}
1 回答
蝴蝶刀刀
TA貢獻1801條經驗 獲得超8個贊
我終于知道為什么了。
$userPasswordError = '<div class="invalid-feedback">Too long.</div>';
$isvalidOrInvalidUserPasword = 'is-invalid';
的變量名isvalidOrInvalidUserPasword錯誤，應該是$isvalidOrInvalidUserPassword（缺少sat密碼）。
如果輸入沒有 class is-invalid，錯誤消息將不可見！
希望這可以幫助！
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