我正在為一個小型預訂系統設計一個小型 PHP 日歷。最后一個功能是阻止一些不可用的日期，我已將其存儲在 PHP 數組中。實現這一目標的最佳方法是什么？請我需要一些關于如何做到這一點的建議。謝謝// Set your timezone!!date_default_timezone_set('Europe/Madrid');// Get prev & next monthif (isset($_GET['ym'])) {    $ym = $_GET['ym'];} else {    // This month    $ym = date('Y-m');}// Check format$timestamp = strtotime($ym . '-01');  // the first day of the monthif ($timestamp === false) {    $ym = date('Y-m');    $timestamp = strtotime($ym . '-01');}// Today (Format:2018-08-8)$today = date('Y-m-j');// Title (Format:August, 2018)$title = date('F, Y', $timestamp);// Create prev & next month link$prev = date('Y-m', strtotime('-1 month', $timestamp));$next = date('Y-m', strtotime('+1 month', $timestamp));// Number of days in the month$day_count = date('t', $timestamp);// 1:Mon 2:Tue 3: Wed ... 7:Sun$str = date('N', $timestamp);// Array for calendar$weeks = [];$week = '';// Add empty cell(s)$week .= str_repeat('<td></td>', $str - 1);for ($day = 1; $day <= $day_count; $day++, $str++) {    $date = $ym . '-' . $day;    if ($today == $date) {        $week .= '<td class="today">';    } else {        $week .= '<td>';    }    $week .= $day . '</td>';    // Sunday OR last day of the month    if ($str % 7 == 0 || $day == $day_count) {        // last day of the month        if ($day == $day_count && $str % 7 != 0) {            // Add empty cell(s)            $week .= str_repeat('<td></td>', 7 - $str % 7);        }        $weeks[] = '<tr>' . $week . '</tr>';        $week = '';    }}如果我在 php 中有一個數組，其日期格式為“2020-08-12”，該數組必須不可用或不可選擇，我該怎么辦。