我正在努力解決一頁上有多個滑塊的問題。我已經修復了一些隨機問題，例如在 stackoverflow 上搜索時圖像未顯示或消失，但對于這個問題，我一直在尋找類似問題的答案，但我不太明白他們是如何修復它的，因為只發布了固定代碼。然而，據我了解，每個滑塊 div 應該有不同的 scripID，但我無法解決它。這是我的代碼：HTML：<div class="card" class="col-md-3"> <!-- Slideshow container --> <div class="slideshow-container"> <!-- Full-width images with number and caption text --> <div class="mySlides fade"> <img src="/images/1.jpg" style="width:100%"> </div> <div class="mySlides fade"> <img src="/images/2.jpg" style="width:100%"> </div> <div class="mySlides fade"> <img src="/images/3.jpg" style="width:100%"> </div> <!-- Next and previous buttons --> <a class="prev" onclick="plusSlides(-1)">❮</a> <a class="next" onclick="plusSlides(1)">❯</a> </div> <br> <!-- The dots/circles --> <div style="text-align:center"> <span class="dot" onclick="currentSlide(1)"></span> <span class="dot" onclick="currentSlide(2)"></span> <span class="dot" onclick="currentSlide(3)"></span> </div> <h2>Header </h2> <hr> <p class="hinfo">headerinfo</p> <p>Text info on the card</p> <p>Grey & Walnut colors<br>W:120 ? D:120 ? H:77</p></div>腳本：var slideIndex = 1;showSlides(slideIndex);// Next/previous controlsfunction plusSlides(n) { showSlides(slideIndex += n);}// Thumbnail image controlsfunction currentSlide(n) { showSlides(slideIndex = n);}function showSlides(n) { var i; var slides = document.getElementsByClassName("mySlides"); var dots = document.getElementsByClassName("dot"); if (n > slides.length) {slideIndex = 1} if (n < 1) {slideIndex = slides.length} for (i = 0; i < slides.length; i++) { slides[i].style.display = "none"; } for (i = 0; i < dots.length; i++) { dots[i].className = dots[i].className.replace(" active", ""); } slides[slideIndex-1].style.display = "block"; dots[slideIndex-1].className += " active";}</script>
1 回答
四季花海
TA貢獻1811條經驗 獲得超5個贊
首先，您需要將 id 添加到您的容器中，并向您的函數添加其他參數，以便它們可以知道哪些滑塊需要更改：
<div class="slideshow-container" id="first">
<!-- Full-width images with number and caption text -->
<div class="mySlides fade">
<img src="/images/1.jpg" style="width:100%">
</div>
<div class="mySlides fade">
<img src="/images/2.jpg" style="width:100%">
</div>
<div class="mySlides fade">
<img src="/images/3.jpg">
</div>
<!-- Next and previous buttons -->
<a class="prev" onclick="plusSlides(-1, 'first', 'firstSliderIndex')">❮</a>
<a class="next" onclick="plusSlides(1, 'first', 'firstSliderIndex')">❯</a>
<br />
<!-- The dots/circles -->
<div style="text-align:center">
<span class="dot" onclick="currentSlide(1, 'first', 'firstSliderIndex')"></span>
<span class="dot" onclick="currentSlide(2, 'first', 'firstSliderIndex')"></span>
<span class="dot" onclick="currentSlide(3, 'first', 'firstSliderIndex')"></span>
</div>
</div>
你的腳本：
<script>
var indexes = {
firstSliderIndex: 1,
secondSliderIndex: 2,
};
showSlides(indexes.firstSliderIndex, 'first', 'firstSliderIndex');
// Next/previous controls
function plusSlides(n, id, index) { // n - number of slide, id - container id, index - current slide number in slider
showSlides(indexes[index] += n, id, index);
}
// Thumbnail image controls
function currentSlide(n, id, index) {
showSlides(indexes[index] = n, id, index);
}
function showSlides(n, id, index) {
var i;
var slides = document.querySelectorAll(`#${id} .mySlides`);
var dots = document.querySelectorAll(`#${id} .dot`);
if (n > slides.length) {
indexes[index] = 1;
}
if (n < 1) {indexes[index] = slides.length}
for (i = 0; i < slides.length; i++) {
slides[i].style.display = "none";
}
for (i = 0; i < dots.length; i++) {
dots[i].className = dots[i].className.replace(" active", "");
}
slides[indexes[index]-1].style.display = "block";
dots[indexes[index]-1].className += " active";
}
</script>
當然，這段代碼可以重構或修改，但這是最簡單的方法
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