你能看一下下面結果中的模式（java）嗎？我預計結果應該給我 3 個組值，但相反它給了我 2 個值，只是我認為我錯過了一些東西。package com.mycompany.testapp;import java.util.regex.Matcher;import java.util.regex.Pattern;/** * * @author bo17a */public class NewClass { public static void main(String[] args){ Pattern mPattern = Pattern.compile("^love (.*?) way you (.*?)$"); Matcher matcher = mPattern.matcher("love the way you lie"); if(matcher.find()){ String[] match_groups = new String[matcher.groupCount()]; System.out.println(String.format("groupCount: %d", matcher.groupCount())); for(int j = 0;j<matcher.groupCount();j++){ System.out.println(String.format("j %d",j)); match_groups[j] = matcher.group(j); System.out.println(match_groups[j]); } } }}我得到的結果是：2love the way you liethe但我的預期結果應該是：3love the way you liethelie更新我嘗試按照回復中的建議添加一組號碼：/* * To change this license header, choose License Headers in Project Properties. * To change this template file, choose Tools | Templates * and open the template in the editor. */package com.mycompany.testapp;import java.util.regex.Matcher;import java.util.regex.Pattern;/** * * @author lee */public class NewClass { public static void main(String[] args){ Pattern mPattern = Pattern.compile("^love (.*?) way you (.*?)$"); Matcher matcher = mPattern.matcher("love the way you lie"); if(matcher.find()){ String[] match_groups = new String[matcher.groupCount()]; System.out.println(String.format("groupCount: %d", matcher.groupCount())); for(int j = 0;j<=matcher.groupCount();j++){ System.out.println(String.format("j %d",j)); match_groups[j] = matcher.group(j); System.out.println(match_groups[j]); } } }}我已經在 Windows 10 JDK 8 Mac OS JDK 8 上嘗試過。那么，這可能是 Java 中的一個錯誤，因為你和我對相同的代碼有不同的結果？
2 回答
狐的傳說
TA貢獻1804條經驗 獲得超3個贊
我的猜測是，您還希望以團隊形式捕捉完整比賽，
^(love (.*?) way you (.*?))$
或者直接在你的計數器上加 1：
測試1
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class RegularExpression{
public static void main(String[] args){
Pattern mPattern = Pattern.compile("^love (.*?) way you (.*?)$");
Matcher matcher = mPattern.matcher("love the way you lie");
if(matcher.find()){
String[] match_groups = new String[matcher.groupCount() + 1];
System.out.println(String.format("groupCount: %d", matcher.groupCount() + 1));
for(int j = 0;j<matcher.groupCount() + 1;j++){
System.out.println(String.format("j %d",j));
match_groups[j] = matcher.group(j);
System.out.println(match_groups[j]);
}
}
}
}
輸出
groupCount: 3
j 0
love the way you lie
j 1
the
j 2
lie
測試2
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class RegularExpression{
public static void main(String[] args){
final String regex = "^(love (.*?) way you (.*?))$";
final String string = "love the way you lie";
final Pattern pattern = Pattern.compile(regex, Pattern.DOTALL);
final Matcher matcher = pattern.matcher(string);
while (matcher.find()) {
System.out.println("Full match: " + matcher.group(0));
for (int i = 1; i <= matcher.groupCount(); i++) {
System.out.println("Group " + i + ": " + matcher.group(i));
}
}
}
}
輸出
Full match: love the way you lie
Group 1: love the way you lie
Group 2: the
Group 3: lie
正則表達式電路
jex.im可視化正則表達式：
九州編程
TA貢獻1785條經驗 獲得超4個贊
顯然，matcher.groupCount()在您的情況下返回 2，因此您只需構造兩個字符串的數組并將數字小于 2 的組復制到其中，即組 0（整個字符串）和組 1（“the”）。如果您matcher.groupCount()在整個代碼中添加 1，它將按預期工作。
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