例如，我有一個程序可以計算中間有空格的 1 + 1，但是如何在我的代碼中使其也可以計算沒有空格的 1 + 1？我正在考慮正則表達式或分割字符串，但我無法成功！有人可以幫我嗎？這是我的代碼：private char[] SPACE = new char[] { ' ' };private void GetAnswer(string clipboardText){ //Loop through all questions and answers// foreach (question q in questionList) { //If we have found an answer that is exactly the same show an Notification// //Startwith zoekt naar alle vragen die matchen vanaf het begin van de zin en Endwith alle vragen die matchen vanaf het eind van de zin// if (q._question.StartsWith(clipboardText) || q._question.EndsWith(clipboardText)) { ShowNotification(q._question, q._answer); break; } } var parts = clipboardText.Split(SPACE); var isValid = true; Double a, b; // Make sure it's format A # B if (parts.Length != 3) return; // Parse first number isValid = Double.TryParse(parts[0], out a); if (!isValid) return; var validOperators = new char[] { '+', '-', ':', 'x', '%' }; // Parse operator if (parts[1].Length != 1) return; var op = parts[1][0]; if (!validOperators.Contains(op)) return; // Parse 2nd number isValid = Double.TryParse(parts[2], out b); if (!isValid) return; // Now calculate the answer string answer = null; switch (op) { case '+': answer = (a + b).ToString(); break; case '-': answer = (a - b).ToString(); break; case ':': if (b == 0) answer = "NaN"; else answer = (a / b).ToString(); break; case 'x': answer = (a * b).ToString(); break; // rekent percentage van een bedrag case '%': answer = (a / b * 100).ToString(); break; default: throw new InvalidOperationException(); } // Show the answer ShowNotification(clipboardText, answer);}提前致謝！
3 回答
偶然的你
TA貢獻1841條經驗 獲得超3個贊
假設您只有兩個數字，如問題中所述，這是解決方案
// this code will work for all of the text mentioned in comments
//string text = "1 + 1";
//string text = "1+1";
//string text = "100.998+ 2000.7";
//string text = "10 + 2000.7";
string text = "100+ 2000";
text = Regex.Replace(text, @"\s+", "");
double num1 = 0;
double num2 = 0;
char operand ;
int startIndex = 0;
for (int i = 0; i < text.Length; i++)
{
// look for first operator
if (isOperator(text[i]) || (i+1) == text.Length) {
if (startIndex == 0) {
double.TryParse(text.Substring(startIndex, i), out num1);
operand = text[i];
startIndex = i + 1;
}
else
{
double.TryParse(text.Substring(startIndex), out num2);
break;
}
}
}
// calculate(num1,operand,num2) // Implement this method with a simple switch case and this will calculate the final answer for you
isOperator 方法的實現：
public static bool isOperator(char opt) {
switch (opt)
{
case '+':
return true;
case '-':
return true;
case '*':
return true;
case '/':
return true;
default:
return false;
}
}
月關寶盒
TA貢獻1772條經驗 獲得超5個贊
實際上我建議首先嘗試從clipboardText. 如果有效，則按其拆分并在拆分時刪除空條目（空格）：
var validOperators = new char[] { '+', '-', ':', 'x', '%' };
char op = validOperators.FirstOrDefault(o => clipboardText.Contains(o));
if (op == default(char))
return;
var parts = clipboardText.Split(new char[] { op}, StringSplitOptions.RemoveEmptyEntries);
最后一件事是現在您的格式將只是數字！零件將只有 2 個元素（希望如此）：
// Make sure it's format A # B
if (parts.Length != 2)
return;
這也意味著取第一個和最后一個數字：
// Parse first number
isValid = Double.TryParse(parts.First(), out a);
if (!isValid)
return;
// Parse last number
isValid = Double.TryParse(parts.Last(), out b);
if (!isValid)
return;
不，您現在可以擺脫運算符轉換和檢查：
// Parse operator
if (parts[1].Length != 1)
return;
var op = parts[1][0];
if (!validOperators.Contains(op))
return;
紫衣仙女
TA貢獻1839條經驗 獲得超15個贊
您可以嘗試var parts = clipboardText.Replace(" ", "");這樣做，這應該使您的輸出始終沒有空間。
private static void GetAnswer(string clipboardText)
{
//Loop through all questions and answers//
foreach (question q in questionList)
{
//If we have found an answer that is exactly the same show an Notification//
//Startwith zoekt naar alle vragen die matchen vanaf het begin van de zin en Endwith alle vragen die matchen vanaf het eind van de zin//
if (q._question.StartsWith(clipboardText) || q._question.EndsWith(clipboardText))
{
ShowNotification(q._question, q._answer);
break;
}
}
var parts = clipboardText.Replace(" ", "");
var isValid = true;
Double a, b;
// Make sure it's format A # B
char? op = null;
int end;
var validOperators = new char[] { '+', '-', ':', 'x', '%' };
// find operator
foreach (char oper in validOperators)
{
if (parts.Contains(oper))
{
end = parts.IndexOf(oper);
op = oper;
}
}
if (!op.HasValue)
return;
// split to argument with op
var arguments = parts.Split(op.Value);
// Parse first number
isValid = Double.TryParse(arguments[0], out a);
if (!isValid)
return;
// Parse 2nd number
isValid = Double.TryParse(arguments[1], out b);
if (!isValid)
return;
// Now calculate the answer
string answer = null;
switch (op)
{
case '+':
answer = (a + b).ToString();
break;
case '-':
answer = (a - b).ToString();
break;
case ':':
if (b == 0)
answer = "NaN";
else
answer = (a / b).ToString();
break;
case 'x':
answer = (a * b).ToString();
break;
// rekent percentage van een bedrag
case '%':
answer = (a / b * 100).ToString();
break;
default:
throw new InvalidOperationException();
}
// Show the answer
ShowNotification(clipboardText,answer);
}
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