由于某種原因，我收到一條錯誤消息，指出該線路currentUser = gar.getAccount(userN);無法訪問，但實際上不應該如此。Garage.getAccount()只是從 a 檢索Hashmap。兩個 if 語句并不相互矛盾，我嘗試添加 else 語句，但無論它說什么，該行都是無法訪問的。package main;import java.util.Scanner;public class Main { private static Scanner input; private static Garage gar; private static Attendant currentUser; private static boolean isManager; public static void main(String[] args) { input = new Scanner(System.in); gar = new Garage(10, 80, 10); currentUser = null; while (currentUser == null) logIn(); } public static void logIn() { System.out.println("Enter username: "); String userN = input.nextLine(); System.out.println("Enter password:"); String userP = input.nextLine(); //if no username, go back if(gar.getAccount(userN) == null) { error("Incorrect username"); return; } if(gar.getAccount(userN).getPassword().equals(userP) == false); { //if entered password doesn't match error("Incorrect password"); return; } currentUser = gar.getAccount(userN); return; } //update to throw error pop-up later public static void error(String er) { System.out.println(er); }}
1 回答
qq_花開花謝_0
TA貢獻1835條經驗 獲得超7個贊
您的語法不正確，if 語句的條件不應以分號結束。
package main;
import java.util.Scanner;
public class Main {
private static Scanner input;
private static Garage gar;
private static Attendant currentUser;
private static boolean isManager;
public static void main(String[] args) {
input = new Scanner(System.in);
gar = new Garage(10, 80, 10);
currentUser = null;
while (currentUser == null)
logIn();
}
public static void logIn() {
System.out.println("Enter username: ");
String userN = input.nextLine();
System.out.println("Enter password:");
String userP = input.nextLine();
//if no username, go back
if(gar.getAccount(userN) == null) {
error("Incorrect username");
return;
}
if(gar.getAccount(userN).getPassword().equals(userP) == false) { //if entered password doesn't match
error("Incorrect password");
return;
}
currentUser = gar.getAccount(userN);
return;
}
//update to throw error pop-up later
public static void error(String er) { System.out.println(er); }
}
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