我有一個如下所示的字符串：[Base Font : IOHLGA+Trebuchet, Font Size : 3.5324998, Font Weight : 0.0] [(X=250.44,Y=223.48499) height=3.5324998 width=4.2910004]DECEMBER 31,[Base Font : IOFOEO+Imago-Book, Font Size : 3.876, Font Weight : 0.0] [(X=307.5,Y=240.48499) height=3.876 width=2.9970093]respectively. The net decrease in the revenue[Base Font : IOHLGA+Trebuchet, Font Size : 3.5324998, Font Weight : 0.0] [(X=49.5,Y=233.98499) height=3.5324998 width=2.5690002](US$ in millions)我想提取“X”的值和關聯的文本并將其轉換為列表。請參閱下面的預期輸出：預期輸出：['X=250.44','DECEMBER 31,']['X=307.5','respectively. The net decrease in the revenue']['X=49.5','(US$ in millions)']我們如何在 Python 中解決這個問題？我的方法：mylist = []for line in data.split("\n"): if line.strip(): x_coord = re.findall('^(X=.*)\,$', line) text = re.findall('^(]\w +)', line) mylist.append([x_coord, text])我的方法沒有發現x_coord和的任何價值text。
3 回答
郎朗坤
TA貢獻1921條經驗 獲得超9個贊
re解決方案：
import re
input = [
"[Base Font : IOHLGA+Trebuchet, Font Size : 3.5324998, Font Weight : 0.0] [(X=250.44,Y=223.48499) height=3.5324998 width=4.2910004]DECEMBER 31,",
"[Base Font : IOFOEO+Imago-Book, Font Size : 3.876, Font Weight : 0.0] [(X=307.5,Y=240.48499) height=3.876 width=2.9970093]respectively. The net decrease in the revenue",
"[Base Font : IOHLGA+Trebuchet, Font Size : 3.5324998, Font Weight : 0.0] [(X=49.5,Y=233.98499) height=3.5324998 width=2.5690002](US$ in millions)",
]
def extract(s):
match = re.search("(X=\d+(?:\.\d*)?).*?\](.*?)$",s)
return match.groups()
output = [extract(item) for item in input]
print(output)
輸出：
[
('X=250.44', 'DECEMBER 31,'),
('X=307.5', 'respectively. The net decrease in the revenue'),
('X=49.5', '(US$ in millions)'),
]
解釋：
\d... 數字\d+...一位或多位數字(?:...)...非捕獲（“正常”）括號\.\d*... 點后跟零個或多個數字(?:\.\d*)?...可選（零或一）“小數部分”(X=\d+(?:\.\d*)?)...第一組，X=number.*?...零個或多個任何字符（非貪婪）\]...]符號$... 字符串結尾\](.*?)$...第二組，]字符串之間和結尾之間的任何內容
斯蒂芬大帝
TA貢獻1827條經驗 獲得超8個贊
嘗試這個：
(X=[^,]*)(?:.*])(.*)
import re
source = """[Base Font : IOHLGA+Trebuchet, Font Size : 3.5324998, Font Weight : 0.0] [(X=250.44,Y=223.48499) height=3.5324998 width=4.2910004]DECEMBER 31,
[Base Font : IOFOEO+Imago-Book, Font Size : 3.876, Font Weight : 0.0] [(X=307.5,Y=240.48499) height=3.876 width=2.9970093]respectively. The net decrease in the revenue
[Base Font : IOHLGA+Trebuchet, Font Size : 3.5324998, Font Weight : 0.0] [(X=49.5,Y=233.98499) height=3.5324998 width=2.5690002](US$ in millions)""".split('\n')
pattern = r"(X=[^,]*)(?:.*])(.*)"
for line in source:
print(re.search(pattern, line).groups())
輸出：
('X=250.44', 'DECEMBER 31,')
('X=307.5', 'respectively. The net decrease in the revenue')
('X=49.5', '(US$ in millions)')
您X=在所有捕獲前面，所以我只做了一個捕獲組，如果重要的話，請隨意添加非捕獲組。
MYYA
TA貢獻1868條經驗 獲得超4個贊
使用帶有命名組的正則表達式來捕獲相關位：
>>> line = "[Base Font : IOHLGA+Trebuchet, Font Size : 3.5324998, Font Weight : 0.0] [(X=250.44,Y=223.48499) height=3.5324998 width=4.2910004]DECEMBER 31,"
>>> m = re.search(r'(?:\(X=)(?P<x_coord>.*?)(?:,.*])(?P<text>.*)$', line)
>>> m.groups()
('250.44', 'DECEMBER 31,')
>>> m['x_coord']
'250.44'
>>> m['text']
'DECEMBER 31,'
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