首頁猿問如何循環 playRound() 函數？

如何循環 playRound() 函數？

JavaScript

慕后森 2023-08-24 21:08:10

我正在制作我的第一個石頭剪刀布游戲。我還沒有正式完成循環，但我正在嘗試將 for 循環應用于 playRound 函數，以便它播放五次?？杀氖俏也淮_定在哪里應用它。我嘗試了幾種方法，但不斷出現錯誤。任何人都可以看看并提供一個選項。代碼如下。function computerPlay() { const number = Math.floor(Math.random() * 1000); if (number % 3 === 0) { return "rock"; } if (number % 3 === 1) { return "paper"; } else { return "scissors"; }}function playRound(playerSelection, computerSelection) { playerSelection = "rock"; computerSelection = computerPlay(); if ( (playerSelection == "rock" && computerSelection == "scissors") || (playerSelection == "scissors" && computerSelection == "paper") || (playerSelection == "paper" && computerSelection == "rock") ) { return "Player Wins!"; } else if ( (playerSelection == "rock" && computerSelection == "paper") || (playerSelection == "paper" && computerSelection == "scissors") || (playerSelection == "scissors" && computerSelection == "rock") ) { return "Computer Wins!"; } else { return "Tie"; }}playerSelection = "rock";computerSelection = computerPlay();console.log(playRound(playerSelection, computerSelection));

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3 回答

慕容森

TA貢獻1853條經驗獲得超18個贊

希望這個例子能給我們一些關于如何進行良好編程的提示

// rock = 0

// paper = 1

// scissor = 2

const valueMap = {

0: 'rock',

1: 'paper',

2: 'scissor'

}

function pick() {

return Math.floor(Math.random() * 3)

}

function decide(p1, p2) {

const pool = [p1, p2]

const sortedPool = pool.sort((a, b) => b.value - a.value)

const diff = sortedPool[0].value - sortedPool[1].value

if (diff === 2) {

return sortedPool[1].name

} else if (diff === 0) {

return 'draw'

} else {

return pool.find(v => v.value === sortedPool[0].value).name

}

function play(times, cb) {

let n = 1

while (n <= times) {

cb(n)

n++

}

play(5, function(n) {

const player1 = {

name: 'Player',

value: pick()

}

const player2 = {

name: 'Computer',

value: pick()

}

const result = decide(player1, player2)

console.log(

`Game ${n}`,

`${player1.name} ${valueMap[player1.value]}`,

` vs `,

`${player2.name} ${valueMap[player2.value]}`,

`>>> Winner ${result}

)

})

反對回復 2023-08-24

UYOU

TA貢獻1878條經驗獲得超4個贊

如果我正確理解你想要什么，你可以用whilea 做一個循環counter，我還改進了你的代碼，使嚴格相等（從==到===），并刪除了冗余代碼

let counter = 1;

function computerPlay() {

const number = Math.floor(Math.random() * 1000);

if (number % 3 === 0) {

return "rock";

} else if (number % 3 === 1) {

return "paper";

} else {

return "scissors";

}

function playRound(playerSelection, computerSelection) {

counter++;

if (

(playerSelection === "rock" && computerSelection === "scissors") ||

(playerSelection === "scissors" && computerSelection === "paper") ||

(playerSelection === "paper" && computerSelection === "rock")

) {

return "Player Wins!";

} else if (

(playerSelection === "rock" && computerSelection == "paper") ||

(playerSelection === "paper" && computerSelection === "scissors") ||

(playerSelection === "scissors" && computerSelection === "rock")

) {

return "Computer Wins!";

} else {

return "Tie";

}

playerSelection = "rock";

while (counter < 6) {

console.log(playRound(playerSelection, computerPlay()));

}

反對回復 2023-08-24

12345678_0001

TA貢獻1802條經驗獲得超5個贊

為最后 3 行添加循環

for (i=0; i<5; i++){

playerSelection = "rock";

computerSelection = computerPlay();

console.log(playRound(playerSelection, computerSelection));

}

編輯：請注意，由于計算機選擇在第二個參數中傳遞，因此 playRound 函數內有多余的調用函數computerPlay()

反對回復 2023-08-24

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如何循環 playRound() 函數？

如何循環 playRound() 函數？