我的代碼旨在將列表列表排序為以下示例。我想將所有 [Y,x,x] 彼此分組。C = [[1,2,3],[4,5,7],[7,8,9],[1,2,4],[4,5,6]]預期輸出請注意,我的Y是粗體的排序 C = [[ 1 ,2,3],[ 1 ,2,4],[ 4 ,5,7],[ 4 ,5,6],[ 7 ,8,9]]c = [[4,5,10],[1,2,3],[4,5,6],[1,7,9],[1,2,8],[4,5,9],[1,7,8],[4,5,12],[9,8,7]]sc = []def sorting(): for a in range(0, len(c)): for b in c[a+1:]: # prevent duplicates if b not in sc: if c[a] not in sc: if c[a][0] == b[0]: sc.append(b) sc.append(c[a]) for z in c: if z not in sc: for a in range(0, len(sc)): if sc[a][0] == z[0]: if sc.count(z) < 1: # insert missing list into intended location sc.insert(a, z) # Append lists that may have been missed (eg. [9,8,7]) for zz in c: if sc.count(zz) < 1: sc.append(zz)sorting()print(sc)錯誤輸出該函數存在語義錯誤,因為它在錯誤的位置輸出 [4,x,x]。如示例所示,所有 [Y,x,x] 都應該分組在一起。[[4, 5, 6], [4, 5, 10], [1, 7, 9], [1, 2, 3], [1, 7, 8], [1, 2, 8], [4, 5, 12], [4, 5, 9], [9, 8, 7]]問題按預期對我的列表進行排序的更專業的功能是什么樣的?我犯了什么錯誤導致了無效的輸出?
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守著星空守著你
TA貢獻1799條經驗 獲得超8個贊
嘗試使用 lambda 函數進行排序函數,以便僅按第一個元素排序。嘗試這個:
c = [[4,5,10],[1,2,3],[4,5,6],[1,7,9],[1,2,8],[4,5,9],[1,7,8],[4,5,12],[9,8,7]]
a = sorted(c, key=lambda parameter: parameter[0]) # sort by first element in item
print(a)
輸出:
[[1, 2, 3], [1, 7, 9], [1, 2, 8], [1, 7, 8], [4, 5, 10], [4, 5, 6], [4, 5, 9], [4, 5, 12], [9, 8, 7]]
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