我正在使用標準實現來實現新的中間件：def my_middleware(get_response): def middleware(request): return get_response(request) return middleware我想得到view_args. 我可以改為基于類的中間件并實現該方法process_view(request, view_func, view_args, view_kwargs)有沒有其他方法可以在我的中間件中獲取這些 view_args、view_kwargs 而無需更改為基于類的中間件？
2 回答
DIEA
TA貢獻1820條經驗 獲得超2個贊
設置為函數process_view(...)的屬性 為middleware(...)
def process_view(request, view_func, view_args, view_kwargs):
"""
do something
"""
def simple_middleware(get_response):
# One-time configuration and initialization.
def middleware(request):
# Code to be executed for each request before
# the view (and later middleware) are called.
response = get_response(request)
# Code to be executed for each request/response after
# the view is called.
return response
middleware.process_view = process_view
return middleware
catspeake
TA貢獻1111條經驗 獲得超0個贊
*?process_view()應該返回None一個HttpResponse對象，否則會出現錯誤。
該函數具有process_view()：
def process_view(request, view_func, view_args, view_kwargs):
? ? # Do something
def simple_middleware(get_response):
? ? # One-time configuration and initialization.
? ? def middleware(request):
? ? ? ? # Code to be executed for each request before
? ? ? ? # the view (and later middleware) are called.
? ? ? ? response = get_response(request)
? ? ? ? # Code to be executed for each request/response after
? ? ? ? # the view is called.
? ? ? ? return response
? ? middleware.process_view = process_view # Here
? ? return middleware
班級有process_view()：
class SimpleMiddleware:
? ? def __init__(self, get_response):
? ? ? ? self.get_response = get_response
? ? ? ? # One-time configuration and initialization.
? ? def __call__(self, request):
? ? ? ? # Code to be executed for each request before
? ? ? ? # the view (and later middleware) are called.
? ? ? ? response = self.get_response(request)
? ? ? ? # Code to be executed for each request/response after
? ? ? ? # the view is called.
? ? ? ? return response
? ? def process_view(self, request, view_func, view_args, view_kwargs):
? ? ? ? # Do something
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