我有一個文件夾，我正在嘗試刪除所有超過 10 天的行。輸入如下：error.log20200122024227-vision.log20200122024730-vision 20200122024930 Missing 20200122024730-vision.log20200520210139 Failed :20200811152053-ibm 20200811152254 Missing20200812164636-ibm_global 20200812164837 Missing20200812210311-ibm_global 20200812210512 Missing20200813080856-ivr 20200813081056 Missing20200813092556-chat_global 20200813092757 Missing20200813125528-ibm_global 20200813125728 Missing20200813163610-acaps_global 20200813163810 Missing20200813172428-mvs_global 20200813172629 Missing20200820204216-pos_global 20200820204417 Missing20200910103742-chatbot_global 20200826103943 Missing20200913103742-chatbot_global 20200826103943 Missing20200914103742-chatbot_global 20200826103943 Missing20200915103742-chatbot_global 20200826103943 Missing20200916103742-chatbot_global 20200826103943 Missing我的輸出應該是：20200910103742-chatbot_global 20200826103943 Missing20200913103742-chatbot_global 20200826103943 Missing20200914103742-chatbot_global 20200826103943 Missing20200915103742-chatbot_global 20200826103943 Missing20200916103742-chatbot_global 20200826103943 Missing這些日志不到 10 天。首先，我需要從 is 行獲取時間戳20200916103742，并檢查它是否小于保留期。如果它被保留，我們必須保留，否則刪除。我傳遞給程序的參數是當前時間戳，保留期為 10 天。所以這意味著我只需要最近 10 天的日志，然后從 error.log 中刪除代碼如下：current_date = sys.argv[1]retention_period = sys.argv[2]old_date = int(current_date ) - int(redention_period*1000000)path = "abc/log/log_test/"error_file = path+"error.log"file = open(error_file)output = []for line in file: print(line) str_log_key = line[0:13] log_key = int(str_log_key) if log_key in range(old_date, current_date): output.append(line)f.close()f = open(error_file, 'w')f.writelines(output)f.close()我收到如下錯誤：if log_key in range(old_date, current_date): TypeError: 'str' object cannot be interpreted as an integer還有其他更好的編碼方式嗎？
3 回答
哆啦的時光機
TA貢獻1779條經驗 獲得超6個贊
這個功能可能會幫助你：
from datetime import date, timedelta
def del_old():
limit = "".join(str(date.today() - timedelta(days = 10)).split("-"))
with open("error.log", "r") as file:
data = file.readlines()
with open("error.log", "w") as file2:
for line in data:
(int(line.lstrip()[:8]) > int(limit)) and file2.write(line)
holdtom
TA貢獻1805條經驗 獲得超10個贊
另一種方法是創建一個新文件：
from datetime import date
errorfile = open(f'error.log', 'r')
errorNew = open(f'error_new.log', 'a+')
current_date = date.today()
for line in errorfile:
date_line = date(int(line[0:4]), int(line[4:6]), int(line[6:8]))
diff = (current_date - date_line)
if diff.days < 10:
errorNew.write(line)
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