我的字典列表如下：[ { "name":"reach", "values":[ { "value":0, "end_time":"2020-09-11T07:00:00+0000" }, { "value":1, "end_time":"2020-09-12T07:00:00+0000" } ] }, { "name":"impressions", "values":[ { "value":0, "end_time":"2020-09-11T07:00:00+0000" }, { "value":4, "end_time":"2020-09-12T07:00:00+0000" } ] }, { "name":"reach", "values":[ { "value":1, "end_time":"2020-09-13T07:00:00+0000" }, { "value":2, "end_time":"2020-09-14T07:00:00+0000" } ] }]我想要集成字典的值鍵，它們的名稱鍵與以下相同：[ { "name":"reach", "values":[ { "value":0, "end_time":"2020-09-11T07:00:00+0000" }, { "value":1, "end_time":"2020-09-12T07:00:00+0000" }, { "value":1, "end_time":"2020-09-13T07:00:00+0000" }, { "value":2, "end_time":"2020-09-14T07:00:00+0000" } ] }, { "name":"impressions", "values":[ { "value":0, "end_time":"2020-09-11T07:00:00+0000" }, { "value":4, "end_time":"2020-09-12T07:00:00+0000" } ] }]但我現在還不知道。我怎樣才能做到這一點？我是Python的初學者，可能不知道一些細節。PS：我想以最小的減速度處理大量數據。
3 回答
素胚勾勒不出你
TA貢獻1827條經驗 獲得超9個贊
您可以使用itertools.groupby
from itertools import chain, groupby
data = sorted(d, key=lambda x: x['name'])
res = [{'name': k, 'values': list(chain.from_iterable(y['values'] for y in g))} for k, g in groupby(data, key=lambda x: x['name'])]
print(res)
輸出：
[{'name': 'impressions',
'values': [{'value': 0, 'end_time': '2020-09-11T07:00:00+0000'},
{'value': 4, 'end_time': '2020-09-12T07:00:00+0000'}]},
{'name': 'reach',
'values': [{'value': 0, 'end_time': '2020-09-11T07:00:00+0000'},
{'value': 1, 'end_time': '2020-09-12T07:00:00+0000'},
{'value': 1, 'end_time': '2020-09-13T07:00:00+0000'},
{'value': 2, 'end_time': '2020-09-14T07:00:00+0000'}]}]
明月笑刀無情
TA貢獻1828條經驗 獲得超4個贊
d = list() # Your initial list (you don't have to copy this line but just assign your initial list to d
result_dict = dict()
for e in d:
if result_dict.get(e['name']):
result_dict[e['name']].extend(e['values'])
else:
result_dict[e['name']] = e['values']
使用此代碼，您可以在 result_dict 中獲取結果作為鍵值，其中鍵是名稱，值是與該名稱對應的值的列表。我認為這種結構更容易維護，并且在轉換數據后您應該繼續處理這種結構。
收到一只叮咚
TA貢獻1821條經驗 獲得超5個贊
您確實應該首先發布您的嘗試，而不是要求別人這樣做。然而：
new_data_dict = {}
for item in data:
if item['name'] not in new_data_dict:
new_data_dict[item['name']] = []
new_data_dict[item['name']] += item['values']
new_data_list = [{'name': name, 'values': values} for name, value in new_data_dict.items()]
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