我是 Codeigniter 4 的新手，所以我問這個問題。事實上，我有兩個不同的型號。首先是tbl_user。其中有很多字段 tbl_user(id, name,duty_station,enlistment_date,dob) // 這里 id 是主鍵。其次是usermos。usermos 有四個字段 [id, user_id, mos_id, extra_mos_id] //這里id是主鍵，user_id是tbl_user的外鍵我已經生成了 get_profile 的控制器...我想將usermos模型訪問到get_profile控制器中。以下是我的代碼標頭<?php namespace App\Controllers;use CodeIgniter\RESTful\ResourceController;use App\Models\MosModel;use App\Models\Additional_mosModel;use App\Models\Api_auth_model;use App\Models\Api_Usermos_Model;控制器public function get_profile() { if (($this->request->getMethod() == 'post') && ($_SERVER['PHP_AUTH_USER'] == AUTHUSER_NAME) && ($_SERVER['PHP_AUTH_PW'] == AUTH_PASSWORD)) { if(!empty($this->request->getPost('id'))){ $user_api_mos_model = new Api_Usermos_Model(); $usermos = $this->user_api_mos_model->findAll(); print_r($usermos); exit; if($profile){ if($usermos){ } $selected_mos = $this->getMosFromID($usermos[0]['mos_id']); $selected_add_mos = $this->getAdd_MosFromID($usermos[0]['additional_mos_id']); $profile['badge'] = $this->getBadgeFromID($profile['badge_id']); // exit; return $this->respond([ "status" => "Success", "message" => "Profile found.", "Common" => ["Title" => "Load Profile API", 'version' => '1.0', 'Description' => 'Load Profile API', 'Method' => 'POST'], "Response" => ["Userdata" => $profile,"mos" => $selected_mos,"additonal_mos" => $selected_add_mos] ]); }else{ return $this->respond([ "status" => "Fail", "message" => "Profile Not found.", "Common" => ["Title" => "Load Profile API", 'version' => '1.0', 'Description' => 'Load Profile API', 'Method' => 'POST'], "Response" => ["Value" => 'Profile Not found.'] ]); } } } }感謝您寶貴的時間。
1 回答
qq_笑_17
TA貢獻1818條經驗 獲得超7個贊
只需在控制器頁面標題部分的頂部定義模型的命名空間并在該控制器頁面中使用即可。例如：
<?php namespace App\Controllers;
use app\models\User;
use app\models\Usermos;
Class UserController extend controller {
public function actionProfile (){
$user = new User();
$user_mos = new Usermos();
}
}
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