我有一個嵌套的 json ，如下所示。我正在嘗試從下面的 json 中獲取城市和標簽的值。 { "5c7a3dd5-29e4-4f5b-9dc8-d2d451906cf1": { "id": "1d14eba1-de9e-4e53-9e9e-619432fd815b", "opinion_id": "3063e6ff-1483-4daf-8e80-41afa43b6348", "paragraph_id": "e6d419fe-5017-47f6-acf1-0e74034aed4a", "position": 7, "city": "Berlin.", "label": "Capital" }, "0c0adcad-992f-4c30-aa58-7bf539f8d649": { "case_id": "6f6e70f7-3257-4f26-a8fa-8cf0e5f97920", "opinion_id": "71b435ff-112c-470b-a36b-c552e54a5605", "paragraph_id": "e6d419fe-5017-47f6-acf1-0e74034aed4a", "position": 3, "city": "Frankfurt.", "label": "Economic Capital" }, "de968cdf-d865-4049-9f7d-f9a68be27432": { "case_id": "2d749a58-412c-4bc8-b268-7d5f7bec3d9a", "opinion_id": "1836c972-d6f7-420b-ba33-8f863cfca482", "paragraph_id": "e6d419fe-5017-47f6-acf1-0e74034aed4a", "position": 4, "city": "Paris.", "label": "Capital" } }我嘗試的是循環遍歷 json 并將值提取到字典列表中。它給我帶來了一個關鍵錯誤。我有點明白了。如果外部json的鍵相同，那么我可以使用text = jsonData['KEY'][i]["city"]with open(json_file_name) as input: jsonData = json.load(input) JSONLength = len(jsonData) data = [] classes = dict() for i in range(0, JSONLength): text = jsonData[i]["city"] label = jsonData[i]["label"] print(text) print(label) data += [(classes[label], text)]
3 回答
開心每一天1111
TA貢獻1836條經驗 獲得超13個贊
迭代字典的值：
with open(json_file_name) as input: jsonData = json.load(input) data = [(values['city'], values['label']) for values in jsonData.values()] print(data
)
出去：
[('Berlin.', 'Capital'), ('Frankfurt.', 'Economic Capital'), ('Paris.', 'Capital')]
青春有我
TA貢獻1784條經驗 獲得超8個贊
嘗試
data = {
"5c7a3dd5-29e4-4f5b-9dc8-d2d451906cf1": {
"id": "1d14eba1-de9e-4e53-9e9e-619432fd815b",
"opinion_id": "3063e6ff-1483-4daf-8e80-41afa43b6348",
"paragraph_id": "e6d419fe-5017-47f6-acf1-0e74034aed4a",
"position": 7,
"city": "Berlin.",
"label": "Capital"
},
"0c0adcad-992f-4c30-aa58-7bf539f8d649": {
"case_id": "6f6e70f7-3257-4f26-a8fa-8cf0e5f97920",
"opinion_id": "71b435ff-112c-470b-a36b-c552e54a5605",
"paragraph_id": "e6d419fe-5017-47f6-acf1-0e74034aed4a",
"position": 3,
"city": "Frankfurt.",
"label": "Economic Capital"
},
"de968cdf-d865-4049-9f7d-f9a68be27432": {
"case_id": "2d749a58-412c-4bc8-b268-7d5f7bec3d9a",
"opinion_id": "1836c972-d6f7-420b-ba33-8f863cfca482",
"paragraph_id": "e6d419fe-5017-47f6-acf1-0e74034aed4a",
"position": 4,
"city": "Paris.",
"label": "Capital"
}
}
city_n_label = [(x['city'],x['label']) for x in data.values()]
print(city_n_label)
輸出
[('Berlin.', 'Capital'), ('Frankfurt.', 'Economic Capital'), ('Paris.', 'Capital')]
慕萊塢森
TA貢獻1810條經驗 獲得超4個贊
嘗試這個
with open(json_file_name) as input:
jsonData = json.load(input)
for k, v in jsonData.items():
print(k) # prints dynamic key
print(v) # prints its corresponding obj
print(v['city']) # will print city of the particular key
print(v['label']) # will print label of the particular key
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