我需要通過按下按鈕觸發繼電器并等待信號然后釋放繼電器。在下面的示例代碼中，該信號是 b2。我是 Python 和 Pi 的新手，但玩得很開心！:)import RPi.GPIO as GPIOGPIO.setmode(GPIO.BCM)from gpiozero import Buttonfrom signal import pauseimport timedef first_button(): print("First Pressed") while True: #do stuff... time.sleep(1) print("waiting...")def second_button(): print("Second Pressed")b1 = Button(23)b1.when_pressed = first_buttonb2 = Button(24)b2.when_pressed = second_buttonpause()當按鈕調用的現有函數仍在運行時，如何檢測按鈕按下情況？
1 回答
小唯快跑啊
TA貢獻1863條經驗 獲得超2個贊
在此解決方案中，您只需打開和關閉輸出
from gpiozero import Button
from signal import pause
import time
pin = #Set a pin
r = LED(pin)
b1 = Button(23)
b1.when_pressed = r.on
b2 = Button(24)
b2.when_pressed = r.off
pause()
這里啟動一個線程來做一些事情：
from gpiozero import Button
from signal import pause
import time
import _thread
run = False
def do_stuff():
while run: #do stuff...
time.sleep(1)
print("waiting...")
def first_button():
global run
print("First Pressed")
run = True
_thread.start_new_thread(do_stuff)
def second_button():
global run
print("Second Pressed")
run = False
b1 = Button(23)
b1.when_pressed = first_button
b2 = Button(24)
b2.when_pressed = second_button
pause()
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