我有以下結構：type A1 struct { IdA1 string NameA1 string key string}type B1 struct { IdB1 string NameB1 string Size string key string}type C1 struct { IdA1 string Name string B1Set B1}我需要創建一個 C1 類型的 []struct，它保存 B1 的 B1Set，B1 超過 2K 個條目，而 A1 只有 10 個條目，一個非常緩慢且低效的實現是循環 A1，并詢問是否B1-key 等于 A1-key 并將結果存儲在映射中，但是..有沒有更好的方法來實現這一點？提前致謝，添加更多信息：它們是兩個不同的 JSON 文件：Json1:[ { "id": "device1", "name": "dev1", "pool": "pool1" }, { "id": "device2", "name": "dev2", "pool": "pool2" } ...]還有另一個 Json：[ { "name": "port1", "size": 10, "pool": "pool1", "status": "active" }, { "name": "port2", "size": 60, "pool": "pool1", "status": "active" }, { "name": "port3", "size": 20, "pool": "pool2", "status": "down" }, { "name": "port8", "size": 100, "pool": "pool2", "status": "active" }, { "name": "port10", "size": 8000, "pool": "pool1", "status": "active" }, ...]
1 回答
MMMHUHU
TA貢獻1834條經驗 獲得超8個贊
這是您想要做的嗎？ https://play.golang.org/p/AZNzQAwRhN0
其作用是構建一個按池對所有端口進行分組的映射。然后它循環遍歷我標記的內容clusters，并通過按值抓取匹配切片來將 的切片分配Port給匹配的切片。ClusterPool
package main
import (
"encoding/json"
"fmt"
)
type Cluster struct {
ID string `json:"id"`
Name string `json:"name"`
Pool string `json:"pool"`
Ports []Port `json:"ports"`
}
type Port struct {
Name string `json:"name"`
Size int `json:"size"`
Pool string `json:"pool"`
Status string `json:"status"`
}
func main() {
var resources []Port
err := json.Unmarshal([]byte(resourceJSON), &resources)
if err != nil {
panic(err)
}
resourcesByPool := make(map[string][]Port)
for _, resource := range resources {
if _, ok := resourcesByPool[resource.Pool]; !ok {
resourcesByPool[resource.Pool] = []Port{}
}
resourcesByPool[resource.Pool] = append(resourcesByPool[resource.Pool], resource)
}
var clusters []Cluster
err = json.Unmarshal([]byte(clusterJSON), &clusters)
if err != nil {
panic(err)
}
for i := 0; i < len(clusters); i++ {
clusters[i].Ports = resourcesByPool[clusters[i].Pool]
}
out, err := json.MarshalIndent(clusters, "", " ")
if err != nil {
panic(err)
}
fmt.Println(string(out))
}
var (
clusterJSON = `[
{
"id": "device1",
"name": "dev1",
"pool": "pool1"
},
{
"id": "device2",
"name": "dev2",
"pool": "pool2"
}
]`
resourceJSON = `[
{
"name": "port1",
"size": 10,
"pool": "pool1",
"status": "active"
},
{
"name": "port2",
"size": 60,
"pool": "pool1",
"status": "active"
},
{
"name": "port3",
"size": 20,
"pool": "pool2",
"status": "down"
},
{
"name": "port8",
"size": 100,
"pool": "pool2",
"status": "active"
},
{
"name": "port10",
"size": 8000,
"pool": "pool1",
"status": "active"
}]`
)
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