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聚合 JavaScript 集合

JavaScript

隔江千里 2023-07-29 16:39:47

我有一個集合，其中我必須僅使用 javascript 來使用聚合。我已經使用 Lodash 庫嘗試過一些事情，但沒有成功。如果你能指導我以某種方式對集合進行分組，”我認為這應該可以解決。var sample = [ { "DESCRIPTOR": "HAPPY", "DESCRIPTOR_ID": 400001, "QUESTION_ID": "A_QUES_1", "CHOICE": "A", "SCORE": 1, "__v": 0 }, { "DESCRIPTOR": "HAPPY", "DESCRIPTOR_ID": 400001, "QUESTION_ID": "A_QUES_2", "CHOICE": "B", "SCORE": 2, "__v": 0 },{ "DESCRIPTOR": "SAD", "DESCRIPTOR_ID": 400002, "QUESTION_ID": "B_QUES_1", "CHOICE": "A", "SCORE": 2, "__v": 0 }, { "DESCRIPTOR": "SAD", "DESCRIPTOR_ID": 400002, "QUESTION_ID": "B_QUES_2", "CHOICE": "B", "SCORE": 2, "__v": 0 } ]我期望像下面這樣的東西， result = [{"DESCRIPTOR": "HAPPY", "TOTAL_SCORE":3}, {"DESCRIPTOR": "SAD", "TOTAL_SCORE":4}]你能幫我只用 JavaScript 編寫這段代碼嗎？謝謝

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2 回答

人到中年有點甜

TA貢獻1895條經驗獲得超7個贊

您可以使用數組歸約方法，

let result = sample.reduce((prev, curr) => {

? ?const descriptorName = curr.DESCRIPTOR;

? ?const index = prev.findIndex((item) => item.DESCRIPTOR === descriptorName);

? ?if(index > -1) {

? ? ? prev[index].SCORE += curr.SCORE;

? ?} else {

? ? ? prev.push({'DESCRIPTOR': descriptorName, 'SCORE': curr.SCORE})

? ?}

? ?return prev;

}, []);

console.log(result);

反對回復 2023-07-29

鳳凰求蠱

TA貢獻1825條經驗獲得超4個贊

下面的代碼根據 DESCRIPTOR_ID 對對象進行分組。首先使用方法遍歷數組Array.prototype.reduce()，獲取descriptor_id并將其作為key，并統計每個key的總分。最后使用方法獲取值Object.values()。

const sample = [

{

DESCRIPTOR: 'HAPPY',

DESCRIPTOR_ID: 400001,

QUESTION_ID: 'A_QUES_1',

CHOICE: 'A',

SCORE: 1,

__v: 0,

{

DESCRIPTOR: 'HAPPY',

DESCRIPTOR_ID: 400001,

QUESTION_ID: 'A_QUES_2',

CHOICE: 'B',

SCORE: 2,

__v: 0,

{

DESCRIPTOR: 'SAD',

DESCRIPTOR_ID: 400002,

QUESTION_ID: 'B_QUES_1',

CHOICE: 'A',

SCORE: 2,

__v: 0,

{

DESCRIPTOR: 'SAD',

DESCRIPTOR_ID: 400002,

QUESTION_ID: 'B_QUES_2',

CHOICE: 'B',

SCORE: 2,

__v: 0,

];

const ret = Object.values(

sample.reduce((prev, c) => {

const p = prev;

const key = c.DESCRIPTOR_ID;

if (!p[key]) p[key] = { DESCRIPTOR: c.DESCRIPTOR, TOTAL_SCORE: c.SCORE };

else p[key].TOTAL_SCORE += c.SCORE;

return p;

}, {})

);

console.log(ret);

反對回復 2023-07-29

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聚合 JavaScript 集合

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