我正在嘗試格式化一個字符串，每個單詞之間的空格數需要根據每個字符串進行更改。我已經完成了計算所需空格數量的代碼。我創建了一個包含多個“”元素的數組，我用這些元素來更改每個單詞之間的空格數。如何打印數組中的 X 到 Y 元素？blankarrayList.get(1-2) // just prints the item in position -1blankarrayList.get(1,2) // just prints items one and two, this works but // doesnt allow me to easily change the number printed (that i know of)public static String format(List<String> myWords) { System.out.println(myWords.get(0) + blankarrayList.get(/*array positions 1 through 3*/) + myWords.get(1) + blankarrayList.get(/*array positions 1 through 3*/) + myWords.get(2) + blankarrayList.get(/*array positions 1 through 3*/) + my words.get(3)); return myWords.get(0);}
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人到中年有點甜
TA貢獻1895條經驗 獲得超7個贊
blankarrayList.get(/*array positions 1 through 3*/) blankarrayList.subList(1, 3); // This gives a sub-list which specified index
因此，您可以將新子列表中的所有元素組合起來，如下所示
System.out.println(myWords.get(0) + StringUtils.join(blankarrayList.subList(1, 3), "") + myWords.get(1) + StringUtils.join(blankarrayList.subList(1, 3), "") + myWords.get(2) + StringUtils.join(blankarrayList.subList(1, 3), "") + my words.get(3));
您也可以像下面這樣編寫所有內容：
System.out.println(StringUtils.join(myWords, blankarrayList.subList(1, 3)));
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