我是 SQL Alchemy 的新手，我需要幫助來實現以下關系：我有兩個表Trends和ClosestTrends，我想聲明兩個一對多關系：表關系在 SQL 中，它將是：ALTER TABLE "closest_trends" ADD FOREIGN KEY ("id_trend_ref") REFERENCES "trends" ("id") ON DELETE CASCADE;ALTER TABLE "closest_trends" ADD FOREIGN KEY ("id_trend_close") REFERENCES "trends" ("id") ON DELETE CASCADE;我嘗試了以下實現：class Trends(Base):? ? __tablename__ = "trends"? ? __table_args__ = (? ? ? ? UniqueConstraint(? ? ? ? ? ? "name", "id_region", "language_iso", name="name_id_region_language"? ? ? ? ),? ? )? ? id = Column(Integer, primary_key=True, index=True, unique=True)? ? .? ? .? ? .? ? closest_trends = relationship("ClosestTrends", backref="Trends")? ?? ? def __str__(self):? ? ? ? return "Trends"class ClosestTrends(Base):? ? __tablename__ = "closest_trends"? ? __table_args__ = (? ? ? ? UniqueConstraint(? ? ? ? ? ? "id_trend_ref", "id_trend_close", name="id_trend_ref_id_trend_close"? ? ? ? ),? ? )? ? id = Column(Integer, primary_key=True, index=True, unique=True)? ? .? ? .? ? .? ??? ? id_trend_ref = Column(? ? ? ? Integer, ForeignKey("trends.id", ondelete="CASCADE"), nullable=False? ? )? ? id_trend_close = Column(? ? ? ? Integer, ForeignKey("trends.id", ondelete="CASCADE"), nullable=False? ? )? ??? ? def __str__(self):? ? ? ? return "ClosestTrends"我無法工作并且收到以下錯誤：sqlalchemy.exc.AmbigouslyForeignKeysError：無法確定關系 Trends.closest_trends 上父/子表之間的聯接條件 - 有多個外鍵路徑鏈接這些表。指定“foreign_keys”參數，提供應被視為包含對父表的外鍵引用的列的列表。有誰知道如何解決這個問題？