我一直在嘗試在顏色欄中繪制一些均勻間隔的刻度線，但到目前為止，我的結果總是給我一個顏色條，刻度線之間的距離與其值成正比，如下圖所示：import numpy as npimport matplotlibimport matplotlib as pltT= [0.01, 0.02, 0.03, 0.04] #values for the colourbar to use in equation in for loopx=np.linspace[0, 8, 100]e=1/(np.exp(x)+1)? ? ? ?#factor used in equation dependent on the x-axis valuesa=6.4*10**(-9)? ? ? ? ?b= 1.51? ? ? ? ? ? ? ? ? # constants for the equationpof6= [number **6 for number in T]norm = matplotlib.colors.Normalize(vmin=np.min(pof6), vmax=np.max(pof6))? #colourbar max and min valuesc_m = matplotlib.cm.cools_m = matplotlib.cm.ScalarMappable(cmap='jet', norm=norm)s_m.set_array([])#below is the for loop that uses one value of T at a time, represented as t in the equationfor t in pof6:? ? ? ? ? ??? ? plt.plot(x, b*x/(((a*t*x**2/(m**2))+1)**2)*e, color=s_m.to_rgba(t))?func = lambda x,pos: "{:g}".format(x)fmt = matplotlib.ticker.FuncFormatter(func)c_bar=plt.colorbar(s_m, format=fmt, ticks=[0.01**6,0.02* 0.03**6, 0.04**6])plt.legend()plt.xlabel('y=E/T')plt.ylabel('$f_{ν_s}$')c_bar.set_label(r'T(K)')plt.show()我嘗試應用網站上建議的一些解決方案，例如將自定義刻度標簽均勻地分布在顏色條上，但尚未成功。
1 回答
aluckdog
TA貢獻1847條經驗 獲得超7個贊
您使用的是線性范數，其中pof值彼此非常接近。使用LogNorm會有所幫助?？潭雀袷交绦蚩梢哉{整以按其格式顯示值**6。
下面的代碼稍微移動了四個函數，因為使用示例中的代碼，所有繪圖似乎都是一致的。至少當我使用類似m=2（m代碼中未定義）的東西時。
import numpy as np
import matplotlib.pyplot as plt
from matplotlib import colors as mcolors
from matplotlib import ticker as mticker
T = [0.01, 0.02, 0.03, 0.04]? # values for the colourbar to use in equation in for loop
x = np.linspace(0, 8, 100)
e = 1 / (np.exp(x) + 1)? # factor used in equation dependent on the x-axis values
a = 6.4 * 10 ** (-9)
b = 1.51? # constants for the equation
pof6 = [number ** 6 for number in T]
norm = mcolors.LogNorm(vmin=np.min(pof6), vmax=np.max(pof6))? # colourbar max and min values
s_m = plt.cm.ScalarMappable(cmap='jet', norm=norm)
s_m.set_array([])
m = 2
for t in pof6:
? ? plt.plot(x, b * x / (((a * t * x ** 2 / (m ** 2)) + 1) ** 2) * e + 10*t**(1/6), color=s_m.to_rgba(t))
func = lambda x, pos: "{:g}**6".format(x**(1/6) )
fmt = mticker.FuncFormatter(func)
c_bar = plt.colorbar(s_m, format=fmt, ticks=pof6)
c_bar.set_label(r'T(K)')
# plt.legend() # there are no labels set, so a default legend can't be created
plt.xlabel('y=E/T')
plt.ylabel('$f_{ν_s}$')
plt.show()
如果您想要圖例，則需要為每條曲線添加標簽，例如：
for t in pof6:
? ? plt.plot(x, b * x / (((a * t * x ** 2 / (m ** 2)) + 1) ** 2) * e, color=s_m.to_rgba(t),
? ? ? ? ? ? ?label=f'$t = {t**(1/6):g}^6$')
plt.legend()
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