我正在嘗試 UnmarshalS 到 DataCollectionFromYAML--- - labels: cats, cute, funny name: "funny cats" url: "http://glorf.com/videos/asfds.com"- labels: cats, ugly,funny name: "more cats" url: "http://glorf.com/videos/asdfds.com"- labels: dogs, cute, funny name: "lots of dogs" url: "http://glorf.com/videos/asasddfds.com"- name: "bird dance" url: "http://glorf.com/videos/q34343.com"type DataFromYAML struct { Labels string `yaml:"labels"` Name string `yaml:"name"` URL string `yaml:"url"`}type DataCollectionFromYAML struct { data []VidedFromYAML}這是我的代碼的一部分，我正在使用 gopkg.in/yaml.v2 包yamlFile, err := ioutil.ReadAll(r) if err != nil { return err } var data models.DataFromYAML err2 := yaml.Unmarshal(yamlFile, data)我收到錯誤消息：無法將 !!seq 解組到 models.DataCollectionFromYAML
1 回答
三國紛爭
TA貢獻1804條經驗 獲得超7個贊
安裝了 包 mainmodels.DataFromYAML的 use 數組[]models.DataFromYAML
import (
"fmt"
"github.com/ghodss/yaml"
)
const data = `---
-
labels: cats, cute, funny
name: "funny cats"
url: "http://glorf.com/videos/asfds.com"
-
labels: cats, ugly,funny
name: "more cats"
url: "http://glorf.com/videos/asdfds.com"
-
labels: dogs, cute, funny
name: "lots of dogs"
url: "http://glorf.com/videos/asasddfds.com"
-
name: "bird dance"
url: "http://glorf.com/videos/q34343.com"
`
type DataFromYAML struct {
Labels string `yaml:"labels"`
Name string `yaml:"name"`
URL string `yaml:"url"`
}
func main() {
var test []DataFromYAML
err := yaml.Unmarshal([]byte(data), &test)
if err != nil {
fmt.Printf("err: %v\n", err)
return
}
fmt.Println(test)
}
輸出：
[{cats, cute, funny funny cats http://glorf.com/videos/asfds.com} {cats, ugly,funny more cats http://glorf.com/videos/asdfds.com} {dogs, cute, funny lots of dogs http://glorf.com/videos/asasddfds.com} { bird dance http://glorf.com/videos/q34343.com}]
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