現在，當有 9 個頁面時，我需要向臨時頁面添加分頁，如下所示： 1 2 3 ... 9我想給出3和9之間的中間點，即1 2 3 ... 6 ... 9當我位于最后/中間頁面時，我還希望有相同的中間子頁面。但這應該由您自己知道如何邁出第一步來完成。我所有的想法都失敗了。有人對這樣的解決方案有想法嗎？完整的工作代碼在這里：<?php if( is_singular() ) return; global $wp_query; /** Stop execution if there's only 1 page */ if( $wp_query->max_num_pages <= 1 ) return; $paged = get_query_var( 'paged' ) ? absint( get_query_var( 'paged' ) ) : 1; $max = intval( $wp_query->max_num_pages ); /** Add current page to the array */ if ( $paged >= 1 ) $links[] = $paged; /** Add the pages around the current page to the array */ if ( $paged >= 3 ) { $links[] = $paged - 1; $links[] = $paged - 2; } if ( ( $paged + 2 ) <= $max ) { $links[] = $paged + 2; $links[] = $paged + 1; } echo '<div class="navigation"><ul>' . "\n"; /** Previous Post Link */ if ( get_previous_posts_link() ) printf( '<li class="prev_post">%s</li>' . "\n", get_previous_posts_link('<') ); /** Link to first page, plus ellipses if necessary */ if ( ! in_array( 1, $links ) ) { $class = 1 == $paged ? ' class="active"' : ''; printf( '<li%s><a href="%s">%s</a></li>' . "\n", $class, esc_url( get_pagenum_link( 1 ) ), '1' ); if ( ! in_array( 2, $links ) ) echo '<li>…</li>'; } /** Link to current page, plus 2 pages in either direction if necessary */ sort( $links ); foreach ( (array) $links as $link ) { $class = $paged == $link ? ' class="active"' : ''; printf( '<li%s><a href="%s">%s</a></li>' . "\n", $class, esc_url( get_pagenum_link( $link ) ), $link ); } /** Link to last page, plus ellipses if necessary */ if ( ! in_array( $max, $links ) ) { if ( ! in_array( $max - 1, $links ) ) echo '<li >…</li>' . "\n"; $class = $paged == $max ? ' class="active"' : ''; printf( '<li%s><a href="%s">%s</a></li>' . "\n", $class, esc_url( get_pagenum_link( $max ) ), $max ); }
1 回答
開滿天機
TA貢獻1786條經驗 獲得超13個贊
一般分頁代碼流可能如下所示：
<?php
function getPageDisplayArray(int $currentPage, int $totalCount, int $pageLen = 10): array
{
$paginationArr[$currentPage] = 1;
$totalPagesToDisplay = floor(($totalCount) / $pageLen);
//Get preceding pages logic
$pagesBefore = $currentPage - 1;
$iBefore = 2; //Number of pages you want befpre the current page
while($pagesBefore > 0 && $iBefore > 0) {
$paginationArr[$pagesBefore--] = 0;
$iBefore--;
}
//Get anteceding pages
$pagesAfter = $totalPagesToDisplay - ($pagesBefore + 1);
$iAfter = min([$pagesAfter, 2]); //Number of pages you want after your current page
while(-$iAfter < 0) {
//Either return the two pages after or don't if there are no pages after
$paginationArr[$iAfter + $currentPage] = 0;
$iAfter--;
}
if($pagesAfter > 2) {
//Calcluate Midpoint
$midpoint = floor($totalPagesToDisplay / 2) + 1;
if(!isset($paginationArr[$midpoint])) {
$paginationArr[$midpoint] = 0;
}
}
//Link the first page always if it hasn't already been set
if(!isset($paginationArr[1])) {
$paginationArr[1] = 0;
}
//Link the final page if it has not already been set.
if(!isset($paginationArr[$totalPagesToDisplay])) {
$paginationArr[$totalPagesToDisplay] = 0;
}
ksort($paginationArr);
return $paginationArr;
}
其中當前頁面、頁面長度和總計數是您的參數。這里將在兩側顯示兩個頁面作為顯示頁面，以及任何仲裁集的第一頁、最后一頁和中間頁。這將返回一個配置數組，該數組將“活動”頁面的值設置為 1，并將所有其他頁面的鍵設置為頁碼，并將值設置為零。剩下的就是按照您認為合適的方式在布局中顯示值。
- 1 回答
- 0 關注
- 95 瀏覽
添加回答
舉報
0/150
提交
取消