我檢查了這個問題的幾種解決方案，當你第一次上傳 a.jpg 時沒問題，但當你再次上傳 a.jpg 時，它就不起作用了。再次上傳 a.jpg 的唯一方法是上傳 b.jpg。我的代碼看起來像這樣 <p>Select file to upload:</p> <asp:FileUpload ID="FileUploader" runat="server" Width="1000px" /> <br />服務器代碼如下所示protected void FileUploadButton_Click(object sender, EventArgs e) { try { //File upload logic. Returns path of uploaded file string filePath = Server.MapPath("~/Files/") + Path.GetFileName(FileUploader.PostedFile.FileName); //File save to server. Saves file name as uploaded by user to folder, "Files" on the server string path = System.IO.Path.Combine("~/Files/",Path.GetFileName(FileUploader.PostedFile.FileName)); FileUploader.SaveAs(Server.MapPath(path)); //Function to insert values in excel sheet to database InsertIntoDatabase(filePath) } catch (Exception Ex) { }//End try }//End FileUpload 我讀過將 fileUploader 放在更新面板上的解決方案。我還嘗試在上傳文件后重命名該文件。這有效，但它破壞了我的邏輯
1 回答
慕田峪7331174
TA貢獻1828條經驗 獲得超13個贊
我重新保存了文件，然后服務器認為它不處理相同的文件
protected void FileUploadButton_Click(object sender, EventArgs e)
{
try
{
//File upload logic. Returns path of uploaded file
string filePath = Server.MapPath("~/Files/") + Path.GetFileName(FileUploader.PostedFile.FileName);
//File save to server. Saves file name as uploaded by user to folder, "Files" on the server
string path = System.IO.Path.Combine("~/Files/",Path.GetFileName(FileUploader.PostedFile.FileName));
string day = DateTime.Now.ToString("ss_mm_hh_dd_MM_yyyy");
FileUploader.SaveAs(Server.MapPath(path));
//Function to insert values in excel sheet to database
InsertIntoDatabase(filePath)
//Resave file to keep track of uploaded files
File.Copy(filePath, day + filePath);
File.Delete(filePath);
}
catch (Exception Ex)
{
}//End try
}//End FileUpload
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