我的問題是在課堂上檢查哈希密碼。這是錯誤：致命錯誤：未捕獲錯誤：無法在 Auth.php:51 中使用 PDOStatement 類型的對象作為數組堆棧跟蹤：#0 index.php(19): Auth->login() #1 {main} 在線 Auth.php 中拋出51if(isset($_POST['login'])) { $username = $_POST['username']; $password = $_POST['password']; #LINE 19 $ui->login($username, $password); }這是我的代碼public function login ( $username, $password ) { $u_login = $this->conn->prepare("SELECT * FROM korisnici WHERE username = :username"); $u_login->bindValue(':username', $username); $u_login->execute(); $u_login->fetch(PDO::FETCH_ASSOC); # LINE 51 $u_v_PASS = password_verify($password, $u_login['password']); if($u_v_PASS->count()) { echo 'uspesno'; } else { }}
1 回答
米琪卡哇伊
TA貢獻1998條經驗 獲得超6個贊
您正在使用 PDOStatement 對象執行提取，但不存儲該提取的結果。相反，您在 PDOStatement 對象本身中查找密碼。嘗試：
public function login ( $username, $password ) {
$u_login = $this->conn->prepare("SELECT * FROM korisnici WHERE username = :username");
$u_login->bindValue(':username', $username);
$u_login->execute();
/*
* Now that the prepared statement has been built and executed, we can
* try to fetch a matching user and store it as $user - this will be an
* array if successful or boolean false if not.
*/
$user = $u_login->fetch(PDO::FETCH_ASSOC);
/* Check that $user is not false and the password_verify returns boolean
* true when comparing the password to the hashed password stored in the
* database.
*/
if ($user && password_verify($password, $user['password'])) {
// User was found and password matched
}
}
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