這是我的單詞表。（實際上我正在使用一個大列表。）bananafishscreamscreamingsuncreamsuncreams我想擴大s'cream。它必須suncream僅匹配。不匹配，scream因為沒有撇號字符。不匹配，suncreams因為末尾的 s 下落不明。我對它的編程不是很好，因為它只匹配所有的單詞。我嘗試過的。這很尷尬。我不知道我在做什么。find = "s'cream"with open('words') as f: for line in f: word = line.strip() skipchars = False for c in find: if c == "'": skipchars = True continue if skipchars: for w in word: if c != w: continue if c not in word: break skipchars = False print(word)
2 回答
慕無忌1623718
TA貢獻1744條經驗 獲得超4個贊
你可以用regex那個會更容易，用.+which的意思替換撇號
.任何字符+1次或多次
import re
words = ['banana', 'fish', 'scream', 'screaming', 'suncream', 'suncreams']
find = "s'cream"
pattern = re.compile(find.replace("'", ".+"))
for word in words:
if pattern.fullmatch(word):
print(word)
HUH函數
TA貢獻1836條經驗 獲得超4個贊
使用正則表達式這很容易：
使用的選擇\w+是與“單詞”字符（如字母）匹配，并且要求至少有 1 個與其映射的字符。
import re
find = "s'cream"
words = [
"banana",
"fish",
"scream",
"screaming",
"suncream",
"suncreams"
]
target_re = re.compile("^{}$".format(find.replace("'", "\w+")))
for word in words:
if target_re.match(word):
print("Matched:", word)
else:
print("Not a match:", word)
"""
output:
Not a match: banana
Not a match: fish
Not a match: scream
Not a match: screaming
Matched: suncream
Not a match: suncreams
"""
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